Can we find a counterexample to the following assertion?

Assume that $f:[-1,1]\to [-1,1]$ an odd function of class $C^3$, and assume thaht $f$ is a concave increasing diffeomorphism of $[0,1]$ onto itself. Then my examples say that $$\frac{1-f(x)^2}{1-x^2}\le f'(x), x\in (0,1).$$

Can we find a counterexample to the following assertion?

Assume that $f:[-1,1]\to [-1,1]$ an odd function of class $C^3$, and assume thaht $f$ is a concave increasing diffeomorphism of $[0,1]$ onto itself. Then my examples say that $$\frac{1-f(x)^2}{1-x^2}\le f'(x),\; x\in (0,1).$$

Can we find a counterexample to the following assertion?

Assume that $f:[0,1]\to [0,1]$ is a concave increasing diffeomorphism. Then my examples say that $$\frac{1-f(x)^2}{1-x^2}\le f'(x), x\in (0,1).$$

Can we find a counterexample to the following assertion?

Assume that $f:[-1,1]\to [-1,1]$ an odd function of class $C^3$, and assume thaht $f$ is a concave increasing diffeomorphism of $[0,1]$ onto itself. Then my examples say that $$\frac{1-f(x)^2}{1-x^2}\le f'(x), x\in (0,1).$$