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A counterexample to: $\frac{1-f(x)^2}{1-x^2}\le f'(x)$-Revisited

Can we find a counterexample to the following assertion?

Assume that $f:[-1,1]\to [-1,1]$ an odd function of class $C^3$, and assume thaht $f$ is a concave increasing diffeomorphism of $[0,1]$ onto itself. Then my examples say that $$\frac{1-f(x)^2}{1-x^2}\le f'(x), x\in (0,1).$$

MathArt
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