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$C\|\sum_i $C\lVert\sum_i a_{ii}\|\rVert \ge \|\lVert(a_{ij})\|$\rVert$ for matrices with entries in a $C^*$-algebra

Let $A$ be a $C^*$-algebra and $(a_{ij}) \in M_n(A)$ be a positive matrix. Does there exist a constant $C \ge 0$ (not depending on the $a_{ij}$) such that $$\|(a_{ij})\| \le C \left\|\sum_i a_{ii}\right\|.$$$$\lVert(a_{ij})\rVert \le C \Bigl\lVert\sum_i a_{ii}\Bigr\rVert?$$

Attempt: Choose a faithful representation $A \subseteq B(H)$. Then $M_n(A) \subseteq M_n(B(H)) = B(H^{n})$ so we have $$\|(a_{ij})\| = \sup_{(x_1, \dots, x_n) \in (H^n)_1} \sum_j \left\|\sum_i a_{ji} x_i\right\|.$$$$\lVert(a_{ij})\rVert = \sup_{(x_1, \dotsc, x_n) \in (H^n)_1} \sum_j \Bigl\lVert\sum_i a_{ji} x_i\Bigr\rVert.$$

How to proceed?

$C\|\sum_i a_{ii}\| \ge \|(a_{ij})\|$ for matrices with entries in a $C^*$-algebra

Let $A$ be a $C^*$-algebra and $(a_{ij}) \in M_n(A)$ be a positive matrix. Does there exist a constant $C \ge 0$ (not depending on the $a_{ij}$) such that $$\|(a_{ij})\| \le C \left\|\sum_i a_{ii}\right\|.$$

Attempt: Choose a faithful representation $A \subseteq B(H)$. Then $M_n(A) \subseteq M_n(B(H)) = B(H^{n})$ so we have $$\|(a_{ij})\| = \sup_{(x_1, \dots, x_n) \in (H^n)_1} \sum_j \left\|\sum_i a_{ji} x_i\right\|.$$

How to proceed?

$C\lVert\sum_i a_{ii}\rVert \ge \lVert(a_{ij})\rVert$ for matrices with entries in a $C^*$-algebra

Let $A$ be a $C^*$-algebra and $(a_{ij}) \in M_n(A)$ be a positive matrix. Does there exist a constant $C \ge 0$ (not depending on the $a_{ij}$) such that $$\lVert(a_{ij})\rVert \le C \Bigl\lVert\sum_i a_{ii}\Bigr\rVert?$$

Attempt: Choose a faithful representation $A \subseteq B(H)$. Then $M_n(A) \subseteq M_n(B(H)) = B(H^{n})$ so we have $$\lVert(a_{ij})\rVert = \sup_{(x_1, \dotsc, x_n) \in (H^n)_1} \sum_j \Bigl\lVert\sum_i a_{ji} x_i\Bigr\rVert.$$

How to proceed?

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Andromeda
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$C\|\sum_i a_{ii}\| \ge \|(a_{ij})\|$ for matrices with entries in a $C^*$-algebra

Let $A$ be a $C^*$-algebra and $(a_{ij}) \in M_n(A)$ be a positive matrix. Does there exist a constant $C \ge 0$ (not depending on the $a_{ij}$) such that $$\|(a_{ij})\| \le C \left\|\sum_i a_{ii}\right\|.$$

Attempt: Choose a faithful representation $A \subseteq B(H)$. Then $M_n(A) \subseteq M_n(B(H)) = B(H^{n})$ so we have $$\|(a_{ij})\| = \sup_{(x_1, \dots, x_n) \in (H^n)_1} \sum_j \left\|\sum_i a_{ji} x_i\right\|.$$

How to proceed?