Let $\mathscr F\in\beta\mathbb N$, where $\beta\mathbb N$ is the set onof ultrafilters on $\mathbb N$, and $\mathscr F\in\beta\mathbb N$. Assume that $l_{\mathscr F}\in\big(\ell^\infty(\mathbb N)\big)^{\!*}$ is the functional which assigns to a bounded sequence $\{a_n\}_{n\in\mathbb N}\subset\mathbb C$, its limit, with respect to the ultrafilter $\mathscr F$. Set $$ X=\mathrm{span}\{l_{\mathscr F}: \mathscr F\in\beta\mathbb N\}. $$$$ X=\mathrm{span}\,\big\{l_{\mathscr F}: \mathscr F\in\beta\mathbb N\big\}. $$ It is relatively straightforward to show that $X$ is dense in $\big(\ell^\infty(\mathbb N)\big)^{\!*}$, in the weak-$*$ topology.
My question is whether $X$ is also dense in the dual-norm topology.