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Post Closed as "Not suitable for this site" by Chris Gerig, Stefan Kohl♦, Anthony Quas, Igor Belegradek, Fernando Muro
Typo in title
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edit approved Oct 10, 2014 at 18:27
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edit approved Oct 10, 2014 at 18:27
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Algebraic topology, Dynamical systmssystems

fixed some typos
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Matthias Wendt
Matthias Wendt
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Let $T^2$ be a 2-torus and $f:T^2\rightarrow T^2$ a smoophsmooth map. Let $f_*:\pi_1(T^2)\rightarrow\pi_1(T^2)$ be the iducendinduced map inon the fudamentalfundamental group $\pi_1$. If $f_*$ has no eigenvalue greater than 1, then all ballballs of T ^ 2 has$T^2$ have subexponential growth by $ f $. Why?

Let $T^2$ be a 2-torus and $f:T^2\rightarrow T^2$ a smooph map. Let $f_*:\pi_1(T^2)\rightarrow\pi_1(T^2)$ be the iducend map in the fudamental group $\pi_1$. If $f_*$ has no eigenvalue greater than 1, then all ball of T ^ 2 has subexponential growth by $ f $. Why?

Let $T^2$ be a 2-torus and $f:T^2\rightarrow T^2$ a smooth map. Let $f_*:\pi_1(T^2)\rightarrow\pi_1(T^2)$ be the induced map on the fundamental group $\pi_1$. If $f_*$ has no eigenvalue greater than 1, then all balls of $T^2$ have subexponential growth by $ f $. Why?

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Jose Santana
Jose Santana
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Algebraic topology, Dynamical systms

Let $T^2$ be a 2-torus and $f:T^2\rightarrow T^2$ a smooph map. Let $f_*:\pi_1(T^2)\rightarrow\pi_1(T^2)$ be the iducend map in the fudamental group $\pi_1$. If $f_*$ has no eigenvalue greater than 1, then all ball of T ^ 2 has subexponential growth by $ f $. Why?