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Ricardo Andrade
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Are all the $R$R-$R$R-bimodules completely reducible?

Let $R$ be the hyperfinite $II_1$ factor and let $X$ be any $R$-$R$-bimodule.

Question  : Is $X$ completely reducible (i.e. a direct integral of irreducible $R$-$R$-bimodules)  ?

Example  : LetIf $(N \subset M)$ is an irreducible, finite depth and finite index (hyperfinite $II_1$) subfactor,
then then $_NL^{2}(M)_N$ is completely reducible.

Are all the $R$-$R$-bimodules completely reducible?

Let $R$ be the hyperfinite $II_1$ factor and let $X$ be any $R$-$R$-bimodule.

Question  : Is $X$ completely reducible (i.e. a direct integral of irreducible $R$-$R$-bimodules)  ?

Example  : Let $(N \subset M)$ an irreducible, finite depth and finite index (hyperfinite $II_1$) subfactor,
then $_NL^{2}(M)_N$ is completely reducible.

Are all the R-R-bimodules completely reducible?

Let $R$ be the hyperfinite $II_1$ factor and let $X$ be any $R$-$R$-bimodule.

Question: Is $X$ completely reducible (i.e. a direct integral of irreducible $R$-$R$-bimodules)?

Example: If $(N \subset M)$ is an irreducible, finite depth and finite index (hyperfinite $II_1$) subfactor, then $_NL^{2}(M)_N$ is completely reducible.

minor edit
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Sebastien Palcoux
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Are all the $R$-$R$ bimodules-bimodules completely reducible?

Let $R$ be the hyperfinite $II_1$ factor and let $X$ be any $R-R$ bimodule$R$-$R$-bimodule.

Question : Is $X$ completely reducible (i.e. a direct integral of irreducible $R-R$ bimodules$R$-$R$-bimodules) ?

Example : Let $N \subset M$$(N \subset M)$ an irreducible, finite depth and finite index (hyperfinite $II_1$) subfactor,
then $_NL^{2}(M)_N$ is completely reducible.

Are all the $R$-$R$ bimodules completely reducible?

Let $R$ be the hyperfinite $II_1$ factor and let $X$ be any $R-R$ bimodule.

Question : Is $X$ completely reducible (i.e. a direct integral of irreducible $R-R$ bimodules) ?

Example : Let $N \subset M$ an irreducible, finite depth and finite index (hyperfinite $II_1$) subfactor,
then $_NL^{2}(M)_N$ is completely reducible.

Are all the $R$-$R$-bimodules completely reducible?

Let $R$ be the hyperfinite $II_1$ factor and let $X$ be any $R$-$R$-bimodule.

Question : Is $X$ completely reducible (i.e. a direct integral of irreducible $R$-$R$-bimodules) ?

Example : Let $(N \subset M)$ an irreducible, finite depth and finite index (hyperfinite $II_1$) subfactor,
then $_NL^{2}(M)_N$ is completely reducible.

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Sebastien Palcoux
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Are all the $R$R$-R$$R$ bimodules completely reducible?

I've removed the second question.
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Sebastien Palcoux
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I've specified the example.
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Sebastien Palcoux
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Sebastien Palcoux
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I've replaced direct sum by direct integral.
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Sebastien Palcoux
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I put the word "completely reducible".
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Sebastien Palcoux
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Sebastien Palcoux
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Sebastien Palcoux
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