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Sebastien Palcoux
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Are there only finitely many maximal irreducible amenable subfactors of aat fixed finite index  ?

A subfactor $N \subset M $ is maximal if it admits no non-trivial intermediate subfactors $N \subset P \subset M $.

Question: are there only finitely many maximal subfactors of a fixed finite index (up to isomorphism)?

Question: Are there only finitely many maximal irreducible amenable subfactors at fixed finite index (Needup to add "finite depth" and "irreducible" ?isomorphism)?

Bonus questionBonus question: let $\alpha$ the index of a finite depth irreducible amenable subfactor.
DoesIs there exist a maximal finite depth irreducible amenable subfactor of index $\alpha$ ?

Are there only finitely many maximal subfactors of a fixed finite index  ?

A subfactor $N \subset M $ is maximal if it admits no non-trivial intermediate subfactors $N \subset P \subset M $.

Question: are there only finitely many maximal subfactors of a fixed finite index (up to isomorphism)?

(Need to add "finite depth" and "irreducible" ?)

Bonus question: let $\alpha$ the index of a finite depth irreducible subfactor.
Does there exist a maximal finite depth irreducible subfactor of index $\alpha$ ?

Are there only finitely many maximal irreducible amenable subfactors at fixed finite index?

A subfactor $N \subset M $ is maximal if it admits no non-trivial intermediate subfactors $N \subset P \subset M $.

Question: Are there only finitely many maximal irreducible amenable subfactors at fixed finite index (up to isomorphism)?

Bonus question: let $\alpha$ the index of a irreducible amenable subfactor.
Is there a maximal irreducible amenable subfactor of index $\alpha$ ?

I fix a grammatical error.
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Sebastien Palcoux
  • 27k
  • 5
  • 74
  • 186

Are there only finitely many maximal subfactors of a fixed finite index ?  

A subfactor $N \subset M $ is maximal if it admits no non-trivial intermediate subfactors $N \subset P \subset M $.

Question: are theythere only finitely many maximal subfactors of a fixed finite index (up to isomorphism)?

(Need to add "finite depth" and "irreducible" ?)

Bonus question: let $\alpha$ the index of a finite depth irreducible subfactor.
Does there exist a maximal finite depth irreducible subfactor of index $\alpha$ ?

Are there only finitely many maximal subfactors of a fixed finite index ?  

A subfactor $N \subset M $ is maximal if it admits no non-trivial intermediate subfactors $N \subset P \subset M $.

Question: are they only finitely many maximal subfactors of a fixed finite index (up to isomorphism)?

(Need to add "finite depth" and "irreducible" ?)

Bonus question: let $\alpha$ the index of a finite depth irreducible subfactor.
Does there exist a maximal finite depth irreducible subfactor of index $\alpha$ ?

Are there only finitely many maximal subfactors of a fixed finite index ?

A subfactor $N \subset M $ is maximal if it admits no non-trivial intermediate subfactors $N \subset P \subset M $.

Question: are there only finitely many maximal subfactors of a fixed finite index (up to isomorphism)?

(Need to add "finite depth" and "irreducible" ?)

Bonus question: let $\alpha$ the index of a finite depth irreducible subfactor.
Does there exist a maximal finite depth irreducible subfactor of index $\alpha$ ?

added 199 characters in body
Source Link
Sebastien Palcoux
  • 27k
  • 5
  • 74
  • 186

A subfactor $N \subset M $ is maximal if it admits no non-trivial intermediate subfactors $N \subset P \subset M $.

Question: are they only finitely many maximal subfactors of a fixed finite index (up to isomorphism)?

Are they only finitely many maximal subfactors of a fixed finite index (upNeed to isomorphism)add "finite depth" and "irreducible" ?)

Bonus question: let $\alpha$ the index of a finite depth irreducible subfactor.
(need to addDoes there exist a maximal finite depth and irreducible subfactor of index $\alpha$ ?)

A subfactor $N \subset M $ is maximal if it admits no non-trivial intermediate subfactors $N \subset P \subset M $.

Are they only finitely many maximal subfactors of a fixed finite index (up to isomorphism)?
(need to add finite depth and irreducible ?)

A subfactor $N \subset M $ is maximal if it admits no non-trivial intermediate subfactors $N \subset P \subset M $.

Question: are they only finitely many maximal subfactors of a fixed finite index (up to isomorphism)?

(Need to add "finite depth" and "irreducible" ?)

Bonus question: let $\alpha$ the index of a finite depth irreducible subfactor.
Does there exist a maximal finite depth irreducible subfactor of index $\alpha$ ?

added 19 characters in body
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Sebastien Palcoux
  • 27k
  • 5
  • 74
  • 186
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Sebastien Palcoux
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  • 186
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Sebastien Palcoux
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Sebastien Palcoux
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  • 186
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Sebastien Palcoux
  • 27k
  • 5
  • 74
  • 186
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