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15 votes
Accepted

Can you build the surreal numbers as a simple direct limit of ordered fields?

Here is one way to get a positive answer to the title question. Theorem. There is a definable class $\mathcal{F}$ of ordered fields, containing isomorphic copies of any given field, and a directed ...
Joel David Hamkins's user avatar
11 votes

Interpreting Conway's remark about using the surreals for non-standard analysis

I will provide some arguments why analysis is best developed using Nonstandard Analysis as opposed to any approach based on the surreals. If you are interested in the constructive/computable content ...
Sam Sanders's user avatar
  • 4,359
9 votes

Can a game be an option of itself?

A surreal number cannot have itself as an option, because numbers are defined inductively: if $L$ and $R$ are sets of numbers, then $\{L|R\}$ is a number. Notice that $L$ and $R$ have to already ...
Brent Yorgey's user avatar
8 votes
Accepted

Interpreting Conway's remark about using the surreals for non-standard analysis

Conway was of course correct in saying that NSA is irrelevant to the surreals, but like Mike I found Conway’s further remarks about NSA puzzling and I am not sure what he had in mind. What I think ...
Philip Ehrlich's user avatar
7 votes
Accepted

The surreal version of $e$

$\DeclareMathOperator{\ee}{e}$If $\varepsilon$ is an infinitesimal surreal, the quantity $\log(1+\varepsilon)$ is actually equal to the formal sum à la Hahn series $\sum \limits_{n \in \mathbb{N}} \...
nombre's user avatar
  • 2,519
6 votes

In surreal numbers, what are the main difficulties so far in defining integration?

A preliminary answer that should really be a comment, but it's too long; everything I'm about to say is better explicated in Integration on the Surreals, O. Costin, P. Ehrlich, 2024, arXiv:2208.14331 ...
6 votes

Why is it said that all surreal numbers with birthdate $<\omega_1$ are isomorphic to a Hardy field?

As Philip Ehrlich had mentioned in the other post, the initial claim of your question is Corollary B of the following paper Matthias Aschenbrenner, Lou van den Dries, Joris van der Hoeven, Filling ...
Joel David Hamkins's user avatar
5 votes
Accepted

Are there results unique to non-standard analysis or surreal numbers that have not been reconciled with classical analysis?

The key paper in this area is Henson and Keisler: C. W. Henson and H. J. Keisler, On the strength of nonstandard analysis}, J. Symbolic Logic, 51 (1986), no. 2, 377-386. The elaborate on the point ...
Mikhail Katz's user avatar
  • 16.6k
5 votes

What are the properties of $\operatorname{No}[i]$?

In addition to the properties mentioned in Joel's answer, $N_0[i]$ is a cogenerator in the category of all fields of characteristic $0$ by a similar argument to the one given by Keith Kearnes here, ...
Alec Rhea's user avatar
  • 10.1k
5 votes
Accepted

What are the properties of $\operatorname{No}[i]$?

The surreal complex field $\text{No}[i]$, known as the surcomplex field, is a proper-class-sized set-saturated algebraically closed field. It is universal for all fields of characteristic 0. Indeed, ...
Joel David Hamkins's user avatar
5 votes

Surreal numbers vs. non-standard analysis

Coming back to the first post. Most of modern mathematics is set-theoretic, that is, it studies sets of different kind, so that reals, real and complex functions, relations on reals, as well as a ...
Vladimir Kanovei's user avatar
5 votes

Interpreting Conway's remark about using the surreals for non-standard analysis

Sam Sanders' answer is very comprehensive. I'll try to add some more context. How do you add a transfer principle to (the initial segments of) the surreal numbers? I tried to explain it with Mikhail ...
Emanuele Bottazzi's user avatar
4 votes

Surreal numbers and the Axiom of Choice

This is not an answer but just a set of comments: A cousin of 1. is a yet unanswered question of J. D. Hamkins. Notice that if an ordered field embeds into $\mathbf{No}$, then so does, as an ordered ...
nombre's user avatar
  • 2,519
1 vote

An extension of the mean-value theorem for integrals?

No, a counterexample would be a function that is negative at and around $a$, but starts becoming positive as it approaches b, such that $$\int_{a}^b f(x)g(x) dx > 0$$ Let $f(x)$ be negative ...
Tim's user avatar
  • 11

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