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20 votes
Accepted

Is there any reason to use paracontrolled calculus over regularity structures?

I don't think that the reason given in the paper by Bailleul and Bernicot is a good one. Basically, they treat an example which is simple enough so that it is still manageable to describe the various ...
Martin Hairer's user avatar
18 votes

What phenomena are better modelled by SDE instead of ODE?

This is a really broad question, but in general noise terms become important if there are few degrees of freedom; for example, chemical reaction kinetics can be accurately described by coupled ODE's, ...
Carlo Beenakker's user avatar
15 votes

Why do stochastic integrals depend on the choice of partitioning points?

First, note that the right comparison is not with the Riemann integral but rather with the Riemann-Stieltjes integral. To be concrete, consider $\int_0^1 X_s dW_s$ where $W$ is Brownian motion and $...
ofer zeitouni's user avatar
15 votes
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A curious martingale

No. see Martingale Convergence Theorem 4 Let X be a continuous martingale. Then, almost surely, one of the following is satisfied $X_\infty=\lim_{t\rightarrow\infty}X_t$ exists and is finite. $\...
Thomas Kojar's user avatar
  • 5,474
11 votes

White noise vs. black noise

Percolation 'noise' is generated by a perfectly good family of random variables, the 'quad-crossing' events. Basically, for every diffeomorphic image of the unit square, this random variable is $1$ if ...
Martin Hairer's user avatar
11 votes

What phenomena are better modelled by SDE instead of ODE?

Brownian motion is an obvious example. Brownian motion described particles dispersed in a liquid that are large enough that the random jossling of the water molecules becomes important. Being one of ...
AccidentalTaylorExpansion's user avatar
9 votes
Accepted

Kolmogorov continuity theorem and Holder norm

One can apply a deterministic result, called Garsia--Rodemich--Rumsey inequality, to estimate $\mathrm{E}[||X||^\alpha_{\gamma;[0,T]}]$. Here is a particular form of this result, which is most ...
zhoraster's user avatar
  • 1,533
9 votes
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Why do we mainly integrate with respect to martingales?

I am aware that this is a really old post, but I feel it is a very important question. My personal favourite answer to this question lies in the theory of rough paths. I will give both a technical ...
Nate River's user avatar
  • 6,155
9 votes
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Maxima of Brownian motion

A good way to measure the set of maxima is the Hausdorff dimension of the set of records, which for BM is a.s. 1/2. Because of time/scale invariance, the dimension is the same for $\alpha B_\cdot$, ...
ofer zeitouni's user avatar
9 votes
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Intuition/elegant reason for why Langevin diffusion converges to $\exp(-U)$?

The reason a Langevin diffusion leaves $\nu(x)=e^{-U(x)}$ invariant is because it is symmetric or reversible with respect to $\nu$. In comparison to general diffusion processes, the ergodic ...
Nawaf Bou-Rabee's user avatar
9 votes
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Definition of infinite-dimensional Gaussian random variable

Even in finite dimensions this definition is more convenient since it is independent of coordinates. If you are interested in geometric applications this is what you need. This definition has the ...
Liviu Nicolaescu's user avatar
9 votes
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How is the Gronwall lemma used in this paper?

$\newcommand\al\alpha\newcommand\be\beta\newcommand\la\lambda$The reasoning in the paper is probably as follows: For real $t\ge0$, letting $$u(t):=2\la(E|X_t|^2-|EX_0|^2)-1,$$ $$\al(t):=-1+2\la(E|X_0|^...
Iosif Pinelis's user avatar
8 votes
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Show that this process is not a martingale

Here's an approach that comes from Li, Xue-Mei, Strict local martingales: examples, Stat. Probab. Lett. 129, 65-68 (2017). ZBL1386.60159, https://arxiv.org/abs/1609.00935. Indeed, she mentions this ...
Nate Eldredge's user avatar
8 votes
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Scalar product of random unit vectors

As noted in the comments, by the spherical symmetry, the distribution of the dot product in both parts of your question is the same that of $X\cdot(1,0,\dots,0)$. Moreover, the distribution of $X$ is ...
Iosif Pinelis's user avatar
8 votes

Question regarding the Wick tensor in white noise analysis

There is a lot of confusion around the concept of "Wick" product. Much of it is due to the following. As you mention, there is a general formula for the Wick product of a collection of ...
Martin Hairer's user avatar
8 votes
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Is a martingale conditioned to be large a submartingale?

No. For a simple counterexample, let's work in discrete time. Consider the following gambling strategy: start with \$0 and bet \$1 on a fair coin flip. If you win, you take your dollar and go home. ...
Nate Eldredge's user avatar
8 votes

Different proof techniques of the Atiyah-Singer index theorem

If you want something in lecture notes/book form, the book Stochastic Analysis on Manifolds by Elton Hsu contains a full exposition of the stochastic approach to the Atiyah-Singer index theorem, along ...
Nate River's user avatar
  • 6,155
7 votes

Does a theory of stochastic differential algebras exist?

Yes. A systematic study of stochastic (differential) algebra could be found in Grenander, Ulf. Probabilities on algebraic structures. Dover Books, 1981. Grenander studied the operation of ...
Henry.L's user avatar
  • 8,071
7 votes
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Geometric characterization of martingales

I do not think Hsu's book is a good place to start with, although it has some strong holds-like details in calculation, neither its depth nor its clarity is comparable to Stroock, Daniel W. An ...
Henry.L's user avatar
  • 8,071
7 votes

Why do stochastic integrals depend on the choice of partitioning points?

To complement the excellent answer by Ofer Zeitouni, let me offer a functional analysis perspective. We want to define an integral of the following form: $\int F(W_t)dW_t=\int F(W_t)W'_tdt$, say, for ...
Kostya_I's user avatar
  • 8,992
7 votes

What phenomena are better modelled by SDE instead of ODE?

Many biological phenomena can be modelled using SDEs or other stochastic models. For example, disease transmission models which keep track of the numbers of infected $I$ and susceptible $S$ ...
S. Catterall's user avatar
6 votes
Accepted

How to prove Feller property without using heat kernel estimates

In the case of a diffusion, (1) is implied for example by having bounded coefficients. This follows immediately from applying BDG to $X_t-x$ and doesn't require (2) which is much harder to get. Note ...
Martin Hairer's user avatar
6 votes

Fundamental Contradiction with Brownian motion

To conclude that something here is wrong, you should be able to indicate a contradiction. Of course, you won't be able to do this, since the two random variables, $M_t:=\sup_{s \in [0,t]} B_s$ and $...
Iosif Pinelis's user avatar
6 votes

Walker whose Velocity is a Brownian Bridge

As Kwaśnicki remarked, the velocity process $v_t$ is a Brownian bridge, which can be represented as: $$ v_t = v_0 (1 - \frac{t}{T}) + v_T \frac{t}{T} + (T - t) \int_0^t \frac{1}{T-s} d B_s \;. $$ (...
Nawaf Bou-Rabee's user avatar
6 votes
Accepted

fractional Brownian Motion driven stochastic integrals

Yes, RPT allows you to define a notion of stochastic integral against fBm for a class of integrands that is larger than what Young's theory allows. Assuming that you're really interested in solving ...
Martin Hairer's user avatar
6 votes
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English translation of "Les aspects probabilistes du contrôle stochastique"

There is no English translation of El Karoui's lecture notes, however her work on Snell envelopes is described in Reflected Solutions of Backward SDE'S, and Related Obstacle Problems for PDE's. For a ...
Carlo Beenakker's user avatar
6 votes
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Filtration exercise

Continuity at zero is included in the RCLL property. If $X(\cdot,\omega)$ is discontinuous at some $t \in (0,t_0)$, then the left and right limits at $t$ (which exist) must differ. Thus there must ...
Yuval Peres's user avatar
  • 14.2k
6 votes
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When are the transition densities of an SDE symmetric?

This question is addressed here. In particular, a diffusion whose transition densities are symmetric is a special case of a $\nu$-symmetric diffusion, and by itself, this symmetry does not uniquely ...
Nawaf Bou-Rabee's user avatar
6 votes

A curious martingale

I think Iosif's Fatou lemma argument can be fixed, as follows. Assume without loss of generality that $X_0 = 0$. Suppose to the contrary that $X_t \to +\infty$ a.s. Then it must be that $\inf_{t \ge ...
Nate Eldredge's user avatar
6 votes

Interpretation of second order term in Fokker-Planck equation

To help the interpretation you may want to rewrite$^\ast$ the Fokker-Planck equation as \begin{align*} \frac{d}{dt}p(x) =& -\nabla\cdot [\tilde{f}p -D\cdot\nabla p],\\ \end{align*} with $D=\tfrac{...
Carlo Beenakker's user avatar

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