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12 votes
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Brauer group of rational numbers

What reference are you reading? For a field $K$, every finite-dimensional central simple $K$-algebra $A$ is isomorphic to ${\rm M}_n(D)$ where $n$ is a positive integer and $D$ is a division ring with ...
KConrad's user avatar
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12 votes
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Brauer groups and field extensions

No: the conic $C:X^2+Y^2+1=0$ splits over the field $L=\mathbb{Q}(x)[y]/(x^2+y^2+1)$, since $(X,Y)=(x,y)$ is an $L$-point of $C$. However $L$ has no subfields algebraic over $\mathbb{Q}$ other than $\...
R.P.'s user avatar
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10 votes
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Reference request: correspondence between central simple algebras and quadratic forms

Everything is in Lam's book Introduction to Quadratic Forms over Fields. Theorem III 5.1 says: All central simple algebra $A$ of dimension $4$ is quaternion. That is $A \cong \left(\frac{a,b}{k}\...
Arctic Char's user avatar
10 votes

Reference request: correspondence between central simple algebras and quadratic forms

In the formulation, presumably on the right side what is intended are 3-dimensional non-degenerate quadratic spaces (up to isomorphism), with discriminant 1 (same as $4^3$ mod squares as John Ma notes)...
8 votes

Elementary classification of division rings

The classification is trivial for a $\,C_1$-field $K$ (that is, such that any homogeneous polynomial in $K[x_1,\ldots ,x_n]$ of degree $<n$ has a nontrivial zero): the only such division algebras ...
abx's user avatar
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7 votes
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Example of a central simple algebra

You can take: $F=\mathbb{C}(X_1,Y_1,\ldots,X_n,Y_n)$ and take the tensor product of quaternion algebras $$A=(X_1,Y_1)_F\otimes_F\cdots\otimes (X_n,Y_n)_F.$$ Here $A$ contains a subfield $E$ ...
GreginGre's user avatar
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6 votes

Reference request: correspondence between central simple algebras and quadratic forms

On a conceptual level, I would like to see this as an instance of a sporadic isomorphism of algebraic groups. Take the conjugation action of $GL_2$ on the space of $2\times 2$-matrices with trace 0, ...
Matthias Wendt's user avatar
6 votes

units in distinct division algebras over number fields---are they definitely not isomorphic as abstract groups?

I know this is a very old question but I saw it just a few days ago. Super-rigidity can indeed be applied not for "higher rank lattices" but for the global points $D^*/F^*$ (which form a lattice in ...
Venkataramana's user avatar
5 votes

What is the quotient group $D^*/{F^*(1+P_D)}$ for a quaternion division algebra $D$ over a local field $F$?

To give an alternative answer, let us first recall the article "Construction of Locally Compact Near-Fields from $p$-Adic Division Algebras" by Detlef Groger: Fix a prime element $\pi_F$ of ...
BPK's user avatar
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4 votes
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What is the quotient group $D^*/{F^*(1+P_D)}$ for a quaternion division algebra $D$ over a local field $F$?

Yes, we can.$\newcommand{\order}{\mathcal{O}}$ $\newcommand{\Z}{\mathbb{Z}}$ $\newcommand{\prim}{\mathcal{P}}$ $\newcommand{\F}{\mathbb{F}}$ First, let me remind you of the following explicit ...
Aurel's user avatar
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3 votes
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Dimension of maximal tori in division algebras

No, there are no such examples, but I don't know any way to attack this by methods of ring theory. The theory of linear algebraic groups gives a very illuminating insight into this matter, by ...
3 votes
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When an algebra isomorphism preserves positive involution

The answer to your general question is NO. Assume for simplicity that $A=B$, and that $A$ is a central simple $K$-algebra. Then $\varphi$ is an inner automorphism by Skolem Noether 's Theorem. Write $\...
GreginGre's user avatar
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3 votes
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On Dirac/ Clifford matrices

If you require that the matrix $C$ in \eqref{2} preserves the involutions \eqref{3}, then you get the consequence $\tilde{\gamma}^\mu = C C^* \tilde{\gamma}^\mu (C C^*)^{-1}$, which then implies that $...
Igor Khavkine's user avatar
3 votes

Elementary proof that a central simple algebra over a field having a maximal subfield is a cyclic algebra

The proof uses as an essential ingredient Proposition 2.2.8, which itself relies on Lemma 2.2.9 telling you that the k-algebras in $M_n(k)$ isomorphic to $k^n$ are conjugate to the subalgebra of ...
thierry stulemeijer's user avatar
3 votes
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Are there any central simple algebras admitting a standard basis?

As suggested by @Kimball I develop my comment. An important class of central simple algebras consists of the cyclic algebras: assume that the field $k$ contains a primitive $n$-th root of unity $\zeta ...
abx's user avatar
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2 votes
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Hasse invariant and the Clifford algbera

You can find some information about this in Lam's book "Introduction to quadratic forms over fields," particularly in the 3rd chapter. I'll give the answer in a "field agnostic" ...
Danny's user avatar
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2 votes
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Crossed product division algebra

Take a prime number $p>2$ and a field $k$ of characteristic zero which does not contain a $p$-th root of unity. Assume that $K/k$ is a Galois extension of order $p$ with a Galois group $\langle g\...
Ehud Meir's user avatar
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