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Algebraic varieties with group operations given by morphisms, or group objects in the category of algebraic varieties, the category of algebraic schemes, or closely related categories.

19 votes

A slick proof of the Bruhat Decomposition for GL_n(k)?

My answer starts off just like Emerton's answer above; you want the $G$-orbits on $G/B\times G/B$. But now, I diverge from Emerton to say that $G/B$ is the space of full flags $F_0\subset F_1\subset \ …
Amritanshu Prasad's user avatar
10 votes
Accepted

Bruhat decomposition for G(R), R local ring or R=Z/p^r

Bruhat decomposition over $\mathbf Z/p^r\mathbf Z$ is precisely the problem we looked at in this paper. We defined several invariants of double cosets, and classified the pairs $(n,k)$ for which, when …
Amritanshu Prasad's user avatar
6 votes

The product of non-commuting semisimple matrices need not be semisimple

$\begin{pmatrix}1&0\\0&0\end{pmatrix}\begin{pmatrix}0&1\\1&0\end{pmatrix}=\begin{pmatrix}0 & 1\\0&0\end{pmatrix}$
Amritanshu Prasad's user avatar
5 votes
1 answer
1k views

kernel of G(Z/p^2 Z)->G(Z/pZ) is the lie algebra of G over Z/pZ?

Let $G$ be an affine algebraic group defined over $\mathbf Z$. The kernel of the natural homomorphism $G(\mathbf Z/p^2\mathbf Z)\to G(\mathbf Z/p\mathbf Z)$, if abelian, is a group which comes along w …
Amritanshu Prasad's user avatar
4 votes

What can representations of affine Weyl groups do?

Here is just one example (I know there are others too): Just as representations of the Hecke algebra associated to a Weyl group correspond to representations of a finite group of Lie type which are i …
Amritanshu Prasad's user avatar
4 votes

Infinite products of representations of the additive group

I address mainly Question C in the simplest special case where $R$ is $\mathbb Q$: In this case you are looking at locally nilpotent endomorphisms of a vector space. Similarity classes of such endomo …
Amritanshu Prasad's user avatar
2 votes
Accepted

Gelfand pair and double coset decomposition

$K\pi^\lambda K$ has a transitive right action of $K$. The stabilizer of $K\pi^\lambda$ for this action is $K\cap \pi^{-\lambda}K\pi^\lambda$. Thus, $K\pi^\lambda K = \coprod_x K\pi^\lambda x$ as $x$ …
Amritanshu Prasad's user avatar