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Applied and theoretical statistics: e.g. statistical inference, regression, time series, multivariate analysis, data analysis, Markov chain Monte Carlo, design of experiments.

1 vote

Why the autoregressive process to generate random time series?

There isn’t any justification that would be applicable to all situations. Rather, this is a modeling choice that has to be justified in the context of your particular problem.
Brian Borchers's user avatar
1 vote
Accepted

Understanding the derivation of a ML-estimator (statistics)

You can simply multiply $\Omega^{-1}$ as given by the author times $\Omega$ and see that the product is $I$. This confirms that the formula for $\Omega^{-1}$ is correct. The key here is that $(I- …
Brian Borchers's user avatar
1 vote
Accepted

Rewrite optimization objective

Here's a solution for the specific case where $f(x)=\| x \|_{1}$ and $g(x)=\| y-Ax \|_{2}$. The same appraoch applies to $g(x)=\| A^{T}(y-Ax) \|_{\infty}$. There are two cases. If $g(0) \leq s$, …
Brian Borchers's user avatar
1 vote

Rewrite optimization objective

You need to start by by being explicit about the "equivalence" between the problems. Do you mean that "For every $s$, there is a $t$ such that if $x^{ * }$ is an optimal solution to the first problem …
Brian Borchers's user avatar
2 votes
Accepted

Understanding the rationale behind "batch means" estimation

The variance of the mean of $n$ random variables is $\mbox{Var}(\bar{x})=\mbox{Var}(\sum_{i=1}^{n} x_{i}/n)$ $\mbox{Var}(\bar{x})=\sum_{i=1}^{n} (1/n)^{2} \mbox{Var}(x_{i})$ $\mbox{Var}(\bar{x})=n …
Brian Borchers's user avatar
1 vote

Convolutive noise removal

A lot depends on $\hat{\eta}(\xi)$. When you convolve this with $\hat{u}$ and $l(\xi)$, you will lose the sparsity if $\hat{\eta}(\xi)$ has broad support. Just how much do you know about the spect …
Brian Borchers's user avatar
1 vote
Accepted

My overdetermined linear system gives both bad and good estimates. Why ?

In using least squares, you normally want the residuals from the various equations to be indpendent of each other. If your $q_{i}$ vectors are imprecise measurements, then this will introduce correla …
Brian Borchers's user avatar
2 votes

Multiple Linear Regression Estimation without full recalc

There's a very large literature on updating solutions to least squares problems as new data are added. The naive formula $\hat{\beta}=(X^{T}X)^{-1}X^{T}y$ can be problematic in practice because of nu …
Brian Borchers's user avatar
1 vote

Solving a particular nonlinear system of equalities

Your problem might be small enough that it is within the range of polynomial optimization techniques based on SDP relaxations of sums of squares problem. This has been implemented in software package …
Brian Borchers's user avatar
3 votes
Accepted

Inverting products of matrices

Now that you've provided some more information, I think I can make some useful suggestions. First, a quick review of linear transformations of multivariate normal random vectors. If $z$ is an MVN …
Brian Borchers's user avatar
2 votes

Inverting products of matrices

You haven't really told us much about the problem. Are you working in conventional single or double precision floating point arithmetic, or are you working in some obscure field? Are the element …
Brian Borchers's user avatar
8 votes

Fit to a normal distribution

There's actually a much broader question that you should be asking yourself here- does it matter whether your data really is normally distributed, or will the procedures that you're going to perform o …
Brian Borchers's user avatar
7 votes

Inverting Hessian matrix

You're really asking the wrong question here... Let's back up a bit. You're attempting to estimate some parameters here, either by a maximum likelihood method or more likely by $\chi^2$ minimization …
Brian Borchers's user avatar
0 votes

Inequality-constrained linear-regression, what is the covariance of the estimator?

"Covariance Matrix" doesn't make a lot of sense in this situation, since there's no multivariate normal distribution around the fitted parameters. You could if you wanted look at a non-ellipsoidal co …
Brian Borchers's user avatar