Search Results
| Search type | Search syntax |
|---|---|
| Tags | [tag] |
| Exact | "words here" |
| Author |
user:1234 user:me (yours) |
| Score |
score:3 (3+) score:0 (none) |
| Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
| Views | views:250 |
| Code | code:"if (foo != bar)" |
| Sections |
title:apples body:"apples oranges" |
| URL | url:"*.example.com" |
| Saves | in:saves |
| Status |
closed:yes duplicate:no migrated:no wiki:no |
| Types |
is:question is:answer |
| Exclude |
-[tag] -apples |
| For more details on advanced search visit our help page | |
Results tagged with inequalities
Search options not deleted
user 8504
for questions involving inequalities, upper and lower bounds.
20
votes
6
answers
6k
views
subadditive implies concave
Let $f:R_+\to R_+$ be smooth on $(0,\infty)$, increasing, $f(0)=0$ and
$\lim_{x\to\infty}=\infty$. Assume also that $f$ is subadditive:
$f(x+y)\le f(x)+f(y)$ for all $x,y\ge 0$. Must $f$ be concave? …
- 213
1
vote
Generalization of the positive semidefinite Grothendieck inequality
to clarify, are you asking if there is a simpler proof if one doesn't care about the optimal constant C? the sharp C seems to be the main point of the paper that you mention. I can imagine a slightly …
- 213