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Results tagged with gelfand-duality
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user 75215
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vote
Accepted
Adjunction via Gelfand duality
$\DeclareMathOperator\Hom{Hom}$
Yes, this is true, and the proof is elementary: let us write $\Omega(A):=\Hom(A,\mathbb{C})$ for the space of characters of $A$, viewed as a subspace of the unit ball o …
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