Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options answers only not deleted user 68708

Alexandrov geometry studies non smooth analogues of Riemannian manifolds with curvature bounded from below or above. It includes spaces with curvature bounded below (briefly $\mathrm{CBB}[\kappa]$) and spaces with curvature bounded above (briefly $\mathrm{CAT}[\kappa]$).

5 votes
Accepted

Codimension of the set of topologically singular points of an Alexandrov space.

Your intuition is correct. Since the Alexandrov space is locally homeomorphic to the cone on the space of directions, your induction hypothesis implies that the statement is true locally, and hence gl …
John Harvey's user avatar
2 votes
Accepted

A property of concave functions on Alexandrov spaces

The base of Perelman's induction for Main Theorem 1.4 (is this what you're talking about?) is in fact a collection of trivial statements about admissible maps $X^n \to \mathbb{R}^{n+1}$. To move to t …
John Harvey's user avatar
3 votes

Gradient of distance function at cut points on Alexandrov spaces

The distance function is semi-concave on all of $M \setminus K$. The additional restriction is unnecessary. The easiest example I can think of for a gradient strictly between zero and one is the cone …
John Harvey's user avatar
5 votes
Accepted

Is the boundary of Alexandrov space again an Alexandrov space?

This is an open problem. It is a special case of the following question: Is it true that every extremal subset is again an Alexandrov space? The answer to this question is "No". Petrunin has …
John Harvey's user avatar
1 vote

Does Alexandrov space satisfy a reverse doubling condition?

The answer is no. In fact, it is not even true for Riemannian manifolds. Consider a flat Riemannian manifold $(M,g)$ of dimension $m$ with diameter $d$ realized by the points $x$ and $y$. Let the vol …
John Harvey's user avatar
3 votes

Why finite dimensional MCS-space implies $\mathbb{R}^m\times cone$ locally?

I'm not sure whether it's generally the case that when you split off an $\mathbb{R}^m$ factor from a cone on an MCS space, the other factor is also a cone on an MCS space. Except, of course, if $m=0$. …
John Harvey's user avatar
3 votes
Accepted

Gluing Alexandrov spaces along parts of boundary

In your specific question, the answer is no. Take two triangles, as two 2-dimensional Alexandrov surfaces. Suppose they each have a side of a given length. Then these sides can be your $E_1$ and $E_2$ …
John Harvey's user avatar
4 votes

Geodesics on convex hypersufaces

As for question 2, the tangent cone of $M$ can be defined as the cone on the space of directions, and the space of directions is the completion of the space of geodesic directions. Therefore every geo …
John Harvey's user avatar
1 vote

Why 2-tori with Gauss curvature $\geq -1$ cannot collapse to segment?

This is not quite an answer, bur certainly too long to be a comment! Here are two sketchy ideas. By following the arguments of Shioya and Yamaguchi, you could make rigorous this argument that the onl …
John Harvey's user avatar