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Descriptive Set Theory is the study of definable subsets of Polish spaces, where definable is taken to mean from the Borel or projective hierarchies. Other topics include infinite games and determinacy, definable equivalence relations and Borel reductions between them, Polish groups, and effective descriptive set theory.

3 votes
Accepted

Hurewicz versus Wadge hierarchy of zero-dimensional Borel sets?

After some thoughts I realized that the answers to Problems 1 and 3 are negative. Namely, each limit Wadge class contains infinitely many Hurewicz non-equivalent spaces. Indeed, take a sequence $(U_n) …
Taras Banakh's user avatar
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4 votes
1 answer
129 views

Hurewicz versus Wadge hierarchy of zero-dimensional Borel sets?

Given two subsets $A,B$ of the Cantor cube $2^\omega$ we write $A\le_W B$ (resp. $A\le_H B$) if there is a continuous (and injective) function $f:2^\omega\to 2^\omega$ such that $f^{-1}(B)=A$. The rel …
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2 votes
Accepted

Can each non-open analytic subgroup of a Polish abelian group be covered by countably many c...

The answer to both problems (1 and 2) is negative: the Polish group $G=\mathbb Z^\omega$ contains a dense meager Borel subgroup $H$ (which can be written as the difference $H=A\setminus B$ of two $F_\ …
Taras Banakh's user avatar
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11 votes
0 answers
142 views

Characterizing compact Hausdorff spaces whose all subsets are Borel

I am interested in characterizing compact topological spaces all of whose subsets are Borel. In this respect I have the following Conjecture. For a compact Hausdorff space $X$ the following conditi …
Taras Banakh's user avatar
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6 votes
1 answer
242 views

Is the space of countable closed covers of the Cantor set analytic?

For an uncountable compact metric space $X$ denote by $K(X)$ be the hyperspace of non-empty compact subsets of $X$, endowed with the Vietoris topology (which is generated by the Hausdorff metric). I …
Taras Banakh's user avatar
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3 votes
0 answers
72 views

Borel complexity of special unions of Polish spaces

Let $X$ be a compact metrizable space and $(A_q)_{q\in\mathbb Q}$ be a family of pairwise disjoint sets, indexed by rational numbers. Assume that the family $(A_q)_{q\in\mathbb Q}$ has the following p …
Taras Banakh's user avatar
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7 votes
1 answer
283 views

Is there a first-countable space containing a closed discrete subset which is not $G_\delta$?

Being motivated by this problem, I am searching for an example of a first-countable regular topological space $X$ containing a closed discrete subset $D$, which is not $G_\delta$ in $X$. It is easy …
Taras Banakh's user avatar
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6 votes
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Is every Borel function a projection of a Borel function with closed graph?

Yes, this is true: by Exercise 13.5 in Kechris' "Classical Descriptive Set Theory", for any Borel function $f:X\to Y$ between Polish spaces there exists a continuous bijective map $i:Z\to X$ from a Po …
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2 votes
0 answers
96 views

Codimension of analytic linear subspaces in Polish vector spaces

Let $A$ be a linear analytic subspace of a Polish vector space $X$. Using Piccard-Pettis Theorem, it is easy to prove that $A$ has uncountable codimension in $X$. If $A$ is of type $F_\sigma$, then ap …
Taras Banakh's user avatar
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6 votes
1 answer
172 views

Can each non-open analytic subgroup of a Polish abelian group be covered by countably many c...

By a result of Laczkovich ('Analytic subgroups of the reals' Proc AMS Vol 126 (1998)), any non-open analytic subgroup of a Polish locally compact group can be covered by countably many closed Haar nul …
Taras Banakh's user avatar
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7 votes
0 answers
168 views

Countable network vs countable Borel network

Definition. A family $\mathcal N$ of subsets of a topological space $X$ is called $\bullet$ a network if for any open set $U\subset X$ and point $x\in U$ there exists a set $N\in\mathcal N$ such that …
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29 votes
Accepted

Closed balls vs closure of open balls

The following theorem (or its corollary) implies negative answer to the original question. Theorem. For any point $x$ of a metric space $(X,d)$ the set $R_x:=\{r>0:cl(B(x,r))\ne \bar B(x,r)\}$ has …
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6 votes
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On continuous perturbations of functions of the first Baire class on the Cantor set

After some thinking I realized that the answer to this question is negative. A counterexample can be constructed by a standard diagonal method of killing all possible candidatures. We shall construct …
Taras Banakh's user avatar
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6 votes
1 answer
328 views

Bernstein sets of large cardinality

A metrizable space $X$ will be called a generalized Bernstein set if every closed completely metrizable subspace $C$ of $X$ has cardinality $|C|<|X|$. It is well-known that the real line contains a ( …
Taras Banakh's user avatar
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2 votes
Accepted

Bernstein sets of large cardinality

After thinking a night on this question and waking up, I realized that the answer is almost trivial: there are restrictions on possible cardinalities of generalized Bernstein set. Any metrizable sp …
Taras Banakh's user avatar
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