Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options answers only not deleted user 582

Algebraic and topological K-theory, relations with topology, commutative algebra, and operator algebras

12 votes
Accepted

Constructing Twisted K-theory

The answer is yes if you're working on the level of $\infty$-categories (and I'm pretty sure no if you're working on the level of homotopy categories). In other words, in the $\infty$-world there's no …
David Ben-Zvi's user avatar
19 votes

Book on Hochschild (co)homology

In addition to Kevin's excellent list: Formality The relation of Hochschild and cyclic homology with loop spaces (eg Jones' theorem) and the circle action on Hochschild homology operadic structure …
7 votes

What is the equivariant cohomology of a group acting on itself by conjugation?

The cochains on G/G can be calculated as the Hochschild cochains of cochains on BG (this uses compactness of G - we'd get a kind of dual picture with Hochschild chains if we looked at free loops in a …
David Ben-Zvi's user avatar
8 votes
Accepted

References for equivariant K-theory

I like the book by Chriss and Ginzburg (Representation Theory and Complex Geometry, https://doi.org/10.1007/978-0-8176-4938-8) very much, and I think it fits many of your requirements.
David Ben-Zvi's user avatar
43 votes
Accepted

What is the equivariant cohomology of a group acting on itself by conjugation?

I asked Dan Freed, who gave a very clean general solution to this problem (as expected). Here it is (all mistakes in the transcription are mine of course). The claim is that the equivariant cohomolog …
David Ben-Zvi's user avatar
12 votes

What are Picard categories, where can I learn more about them, and why should I care to?

Determinants are discussed (in a language relevant to this current question) in this MO question. One place Picard categories naturally appear is as fundamental (aka Poincare) groupoids -- specifical …
David Ben-Zvi's user avatar