Search Results
| Search type | Search syntax |
|---|---|
| Tags | [tag] |
| Exact | "words here" |
| Author |
user:1234 user:me (yours) |
| Score |
score:3 (3+) score:0 (none) |
| Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
| Views | views:250 |
| Code | code:"if (foo != bar)" |
| Sections |
title:apples body:"apples oranges" |
| URL | url:"*.example.com" |
| Saves | in:saves |
| Status |
closed:yes duplicate:no migrated:no wiki:no |
| Types |
is:question is:answer |
| Exclude |
-[tag] -apples |
| For more details on advanced search visit our help page | |
Results tagged with polynomials
Search options not deleted
user 490128
Questions in which polynomials (single or several variables) play a key role. It is typically important that this tag is combined with other tags; polynomials appear in very different contexts. Please, use at least one of the top-level tags, such as nt.number-theory, co.combinatorics, ac.commutative-algebra, in addition to it. Also, note the more specific tags for some special types of polynomials, e.g., orthogonal-polynomials, symmetric-polynomials.
4
votes
Is there a $3$-commutative algebra?
Let $a,b,c$ be basis vectors over some commutative associative algebra $X$. Consider the algebra $A$ spanned by these basis vectors over $X$, with the multiplication rules $pq=q$ for all $p,q \in \{a, …
- 1,245
4
votes
0
answers
140
views
Does an instance of this generalisation of the determinant exist?
In such a way that the entries of $T(A)$ degree $d$ homogeneous polynomials in the entries of $A$?
Or do we need to take a subalgebra of the $n×n$ matrices for this? …
- 1,245