Search Results
Search type | Search syntax |
---|---|
Tags | [tag] |
Exact | "words here" |
Author |
user:1234 user:me (yours) |
Score |
score:3 (3+) score:0 (none) |
Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
Views | views:250 |
Code | code:"if (foo != bar)" |
Sections |
title:apples body:"apples oranges" |
URL | url:"*.example.com" |
Saves | in:saves |
Status |
closed:yes duplicate:no migrated:no wiki:no |
Types |
is:question is:answer |
Exclude |
-[tag] -apples |
For more details on advanced search visit our help page |
Spectrum, resolvent, numerical range, functional calculus, operator semigroups. Special classes of operators: compact, Fredholm, dissipative, differential, integral, pseudodifferential, etc.
4
votes
1
answer
97
views
The adjoint of the Cesaro operator on $H^p$
For each $f=\sum_{k=0}^\infty b_kz^k\in H^p(\mathbb{D})$, $1<p<\infty$, we consider the following operators;
$$
C(f)(z)=\sum_{n=0}^\infty \left(\frac{1}{n+1}\sum_{k=0}^n b_k\right)z^n
$$
and
$$
A(f)( …