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Homotopy theory, homological algebra, algebraic treatments of manifolds.
5
votes
Accepted
Relationship between $H_*(X, A)$ and $H_*(Y \cup_f X, Y)$? $\pi_*(X, A)$ and $\pi_*(Y \cup_f...
Expanding my comment:
The natural map $H_*(X,A)\rightarrow H_*(X\cup_f Y, Y)$ is an isomorphism, this is the so-called "excision axiom".
The map $\pi_i(X,A)\rightarrow \pi_i(X\cup_f Y, Y)$ is an iso …
18
votes
Accepted
Is $SU(3)/SO(3)$ cobordant with a mapping torus?
The mapping torus $T$ of the complex-conjugation-map $\mathbb{C}P^2 \rightarrow \mathbb{C}P^2$ does the job.
For example by running the Serre spectral sequence with local coefficients, you obtain th …
32
votes
Accepted
What is the group of pointed homotopy classes of maps from $S^3 \times S^3$ to $S^3$?
We have that $S^3 \simeq \Omega \mathbb{H}P^{\infty}$, so by adjointness we can as well consider the group of maps $[\Sigma S^3 \times S^3, \mathbb{H}P^{\infty}]$. It is well-known that $[X,\Omega Y] …
14
votes
Homology equivalence and isomorphism on $\pi_1$ not enough for homotopy equivalence?
This is a modification of Anders's suggestion:
Take $X=M(\mathbb{Z}[\frac{1}{2}],2)$ to be the Moore space with $H_2(X) = \mathbb{Z}[\frac{1}{2}]$. We can have $\mathbb{Z}/2$ act on $X$ this by a sig …
16
votes
Which singular homology classes can be represented by embedded manifolds?
The question in the title differs from the question spelled out in the post: In the title, you ask for embedded manifolds, in the post you ask for just maps from manifolds. I think the version of the …
7
votes
Formula for compositions of Steenrod squares that produce a form in the top degree
To add onto the very nice explicit answer of Tyrone, here's another perspective which you might find interesting: Both Stiefel-Whitney classes and Wu classes can be generalized to arbitrary $\mathbb{F …
38
votes
Accepted
Simply-connected rational homology spheres
In dimension 4, we have the following:
Simply-connectedness implies that $H_1(M)=0$. The condition that $M$ be a rational homology sphere implies that $H_2(M), H_3(M)$ are finitely generated torsion g …
7
votes
Given $f: X \to Y$, $g: X \to Z$, when does it exists $h: Y \to Z$ such that $hf \simeq g$?
By replacing $f: X\to Y$ by a CW inclusion you can attack this with classical obstruction theory. I think the obstructions will lie in relative cohomology groups with local coefficients, $H^{n+1}(Y,X; …
37
votes
Accepted
If $\Omega X \simeq \Omega Y$ then is $X \simeq Y$ for $X,Y$ simply connected?
To expand on my comment: As written (i.e. without requiring a map $f:X\to Y$), this is false in general. For an example, write $S^2$ as homogeneous space, $S^2=SU(2)/U(1)$. This exhibits $S^2$ as the …
14
votes
Simplest example of non-trivial Toda bracket in spaces
The definition you've most likely encountered is the following:
For maps $W\xrightarrow{f} X \xrightarrow{g} Y \xrightarrow{h} Z$, such that adjacent maps compose to $0$, $g$ extends to a map on th …
11
votes
Accepted
Lifting of map from $S^3$ to itself
No. The reason this holds in the complex case (any degree $0$ map $S^1 \to S^1$ factors through $\exp: \mathbb{R}i\to S^1$) is that in that case the exponential map is a covering map, in particular a …
14
votes
Accepted
Direct limits in homotopy category
This is the classical $\mathrm{lim}^1$ phenomenon: While $\mathrm{Map}(X,Y) = \operatorname{lim}\mathrm{Map}(X_n,Y)$ (a homotopy limit), on homotopy classes it is not true that $[X,Y] \cong \operatorn …
8
votes
Accepted
Why is $bo$ not flat?
Let me me write $ko$ for connective $KO$, since I'm more used to that. If $ko_*ko$ were a flat $ko_*$-module, then by basechange to $H\mathbb{Z}$, $H\mathbb{Z}_*ko$ would be a flat $\mathbb{Z}$-module …
15
votes
Accepted
Hairy ball theorem for odd-dimensional spheres
The Lefschetz fixed point theorem implies that any $f: S^n \to S^n$ without fixed points has degree $(-1)^{n+1}$. But an even map $S^n \to S^n$ has even degree, since it factors as
$$
S^n \xrightarrow …
3
votes
Accepted
(Lower) homotopy groups from triangulations
Being a manifold or the dimension restriction $k\leq n$ doesn't matter, the following applies to finite simplicial complexes in general:
As others have explained, if the fundamental group is not finit …