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Linear representations of algebras and groups, Lie theory, associative algebras, multilinear algebra.
3
votes
When representations of a Borel subgroup can be extended to a parabolic subgroup
Yes. Write $P_\alpha = (SL_2) \ltimes ((\ker \alpha) Rad(P_\alpha))$ where $\ker\alpha$ is the subgroup of $T$. The necessity of your condition is about getting the $SL_2$ to act. Once you impose it, …
5
votes
2
answers
380
views
A general theory of multiplicity-free actions of $G\times H$?
There seem to be a bunch of different results of the form "This nice
representation $V$ of $G\times H$ breaks up as $\bigoplus_\lambda V_\lambda
\otimes W_\lambda$, where the $(V_\lambda)$ are distinc …
9
votes
1
answer
461
views
The highest root of an ADE quiver
Let $\Gamma$ be a finite subgroup of $SL_2({\mathbb C})$, and $Q$ the set of
its irreducible representations. McKay makes $Q$ into a directed graph by
having $V \to W$ if $W \leq V \otimes {\mathbb C} …
15
votes
2
answers
673
views
Relating two characterizations of ${\mathfrak sl}_{n > 2}$ among simple Lie algebras
Let $\mathfrak g$ be a finite-dimensional simple Lie algebra over $\mathbb C$.
Theorem 1. The highest root is perpendicular to all but one simple root, except in the case ${\mathfrak g}={\mathfrak sl …
6
votes
1
answer
241
views
Inner product on $V_{-\rho}$?
Prologue. To $M^n$ a compact real manifold with frame bundle $F$ (a principal $GL_n$ bundle), we associate a line bundle using the representation $M\mapsto \sqrt{|\det M|}$, the bundle of half-densiti …
24
votes
Peter-Weyl vs. Schur-Weyl theorem
Yes. In combinatorics this is known as Robinson-Schensted-Knuth vs. just Robinson-Schensted. (Properly speaking the latter is about a yet smaller duality, $\mathbb C[S_n] = \bigoplus_{\lambda\vdash n} …
12
votes
What is Borel-de Siebenthal theory?
In my head at least, part of it is this...
Let G be reductive. Consider the following algorithm:
Extend one component of the Dynkin diagram to its affine diagram, by attaching the lowest root.
From …
6
votes
Frobenius - Schur indicator and irreducible representations over R
I've always thought of this formula as an amusing accident. You say "I can go through the proofs", so I don't know if what I'll say helps any more than that, but here goes.
If $M$ is any endomorphis …
7
votes
How to write $\mathbb{C}[G/U_-]=\oplus_{\lambda} V_{\lambda}$ explicitly?
It's slightly nicer to look at $M_n // U_-$ instead of $GL(n) // U_-$, since then we're looking at a subring of invariants inside a polynomial ring. Namely,
the subring generated by all determinants t …
3
votes
Accepted
Orbits of Root Vectors
If $\alpha$ is a long root (e.g. if $\mathfrak g$ is simply-laced), then $e_\alpha$ is in the $G$-orbit of the high weight vectors. Projectively, its orbit looks like $G/P_\Theta$ where $P_\theta$ is …
14
votes
Accepted
Why does the degree of the variety of rank at most $r$ $n\times n$ matrices equal dim$S_{(n-...
There are a number of better statements (i.e. yes, this is "well-known").
To begin with, wouldn't you rather have the character of this representation, instead of just its dimension? You can get that …
3
votes
Accepted
Representation of quotient group
Yes, if $H$ is closed (i.e. not some irrational-flow subgroup inside the closed subgroup $Z(G)$).
8
votes
Occurrence of the trivial representation in restrictions of Lie group representations
Consider the case that $H$ is a maximal torus of $G'$, and your $G = G' \times H$. (Well, you said $G,H$ semisimple, but I'm going to pretend you meant reductive, because really you should have.)
Then …
2
votes
Highest weights of the restriction of an irreducible representation of a simple group to a L...
This is not a complete answer, but maybe it will be of use.
You're asking which $L$-high weights $\mu$ occur in the $G$-irrep $V_\lambda$. Let me say that $\mu$ occurs classically if for some $N>0$, …
12
votes
Who colored in my Dynkin diagrams?
Naively, there can be no reasonable way of distinguishing the red nodes from green in the case $A_{even}$, as the Dynkin diagram automorphism switches them.
Less naively, there is indeed a way of dis …