Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options not deleted user 391

for questions on geometric invariant theory (or GIT), including stability criteria and symplectic quotients.

3 votes

Toric varieties as quotients of affine space

Let me advertise the polytopal point of view. Start with $T^k$ acting on ${\mathbb A}^n$ linearly, i.e. we have a map $T^k \to T^n$. The $T^n$-moment polytope of ${\mathbb A}^n$ is just the orthant $ …
Allen Knutson's user avatar
15 votes

Quotients by the additive group $\mathbb G_a$

In general, the only definition I know of GIT quotient is $Proj$ of the invariant ring. The obvious statements one can make about the rational map $Proj\ R\to Proj\ R^G$ are that it collapses $G$-orbi …
Allen Knutson's user avatar
4 votes

Are orbits of an affine algebraic monoid affine?

Let $SL_2$ act on ${\mathbb A}^2$. This has two orbits, $\{\vec 0\}$ and its complement, and the latter is not affine.
Allen Knutson's user avatar
3 votes

The canonical divisor of the Hilbert scheme $Hilb^n P^2$?

$n=1$ already tells you that the anticanonical divisor is going to be nicer than the canonical, in that it's effective. There, the divisor given by the three coordinate lines is anticanonical. Next s …
Allen Knutson's user avatar
1 vote
Accepted

Configuration space of flags

There are many GIT quotients, since to define one requires a choice of $G$-line bundle, so a pair of naturals for each $F$. There's an obvious democratic choice -- $(a,b) = (1,1)$ for every $F$ -- b …
Allen Knutson's user avatar
15 votes
Accepted

Partial (or complete) flag varieties as GIT quotients of affine spaces

If you're willing to quotient by a nonreductive group, then $M_n//B$ will get you the $GL(n)$ flag manifold. (People are usually afraid to do so, worrying that the ring of invariants won't be Noetheri …
Allen Knutson's user avatar