Search Results
| Search type | Search syntax |
|---|---|
| Tags | [tag] |
| Exact | "words here" |
| Author |
user:1234 user:me (yours) |
| Score |
score:3 (3+) score:0 (none) |
| Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
| Views | views:250 |
| Code | code:"if (foo != bar)" |
| Sections |
title:apples body:"apples oranges" |
| URL | url:"*.example.com" |
| Saves | in:saves |
| Status |
closed:yes duplicate:no migrated:no wiki:no |
| Types |
is:question is:answer |
| Exclude |
-[tag] -apples |
| For more details on advanced search visit our help page | |
Results tagged with eigenvalues
Search options not deleted
user 38468
eigenvalues of matrices or operators
10
votes
Accepted
Eigenvalues of a matrix with entries involving combinatorics
Clearly, these statements 1 and 2 together imply that the eigenvalues
are $1,l,\ldots, l^{n-1}$.
We will assume throughout that $l\geq 2$, otherwise the statement is obvious. …
- 5,186
3
votes
Accepted
Proving 2 matrices have the same trace
Let's call $C=A-B$. Then you have $C^2=I_n$ and $BC-CB$ is invertible. You want to show that $C$ has an equal dimension of $1$ and $(-1)$ eigenspaces, which in turn implies both the equality $tr(A)=tr …
- 5,186
2
votes
When is this matrix singular?
For $\phi_j=0$ and $t_k=k$ you have (up to a constant) the matrix $A_{jk}= \lambda_j^k - \lambda_j^{-k}$ where $\lambda_j=\exp( i w_j)$. You can factor out $\lambda_j-\lambda_j^{-1}$
to get a matrix $ …
- 5,186