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Questions about abstract measure and Lebesgue integral theory. Also concerns such properties as measurability of maps and sets.
2
votes
0
answers
62
views
Extending a Baire-to-Baire-Kernel to a Borel-to-Borel Kernel
It is well known that a finite measure on the Baire $\sigma$-algebra of a, say, compact Hausdorff space can be extended to a unique regular measure defined on the Borel $\sigma$-algebra. The Baire $\s …
3
votes
1
answer
911
views
Atoms of a sequence of Sigma-algebras
I'm trying for some time now to prove or disprove the following conjecture to no avail:
Let $S$ be a set and let $(\Sigma _n)$
be a sequence of countably generated
$\sigma$-algebras on $S$ sat …
5
votes
1
answer
1k
views
Are measurable functions almost surely constant on atoms?
Let $(\Omega,\Sigma,\mu)$ be a probability space. A $\mu$-atom is an $A\in\Sigma$ such that $\mu(A)>0$ and for all $B\in\Sigma$ such that $B\subseteq A$, either $\mu(B)=\mu(A)$ or $\mu(B)=0$ holds.
N …
2
votes
1
answer
160
views
How small can a set admitting a nonatomic finite measure be?
Is it consistent that there exists a nonzero atomless finite measure
on some $\sigma$-algebra on a cardinal $\kappa$ satisfying $\kappa<\mathfrak{c}$? Can
there be such a measure on $\omega_1$ …
2
votes
0
answers
35
views
When does a measure-valued map admit a continuously parametrized density function?
Let $X$ and $Y$ be Polish spaces, let $\mathcal{P}(Y)$ be the space of Borel probability measures on $Y$ endowed with the smallest $\sigma$-algebra such that all functions of the form $\nu\mapsto\nu(A …
7
votes
1
answer
571
views
Random Functions and Transition Probabilities
Let $(S,\mathcal{S})$ and $(T,\mathcal{T})$ be measurable spaces. A transition probability from $S$ to $T$ is a function $\pi:S\times\mathcal{T}\to [0,1]$ such that $\pi(s,\cdot)$ is a probability mea …
1
vote
0
answers
191
views
Can random elements be defined in terms of a measure algebra?
Let $(\Omega,\Sigma,\mu)$ be a probability space, $(X,\mathcal{X})$ be a measurable space and $R(\Omega,X)$ be the set of equivalence classes of measurable functions from $\Omega$ to $X$ under almost …
10
votes
0
answers
3k
views
Quotients of Measurable Spaces?
Let $(\Omega,\Sigma)$ be a measurable space and $\Pi$ be a partition of $\Omega$. There is a projection $\pi:\Omega\to\Pi$ that maps each $\omega\in\Omega$ to the unique partition cell in $\Pi$ contai …
90
votes
9
answers
17k
views
Demystifying the Caratheodory approach to measurability
Nowadays, the usual way to extend a measure on an algebra of sets to a measure on a $\sigma$-algebra, the Caratheodory approach, is by using the outer measure $m^* $ and then taking the family of all …
10
votes
1
answer
775
views
Proof of Lomnicki and Ulam on infinite product probability spaces
Given an arbitrary, nonempty family $(\Omega_i,\Sigma_i,\mu_i)_{i\in I}$ of probability spaces, there exists a probability measure $\mu$ on $\otimes_i\Sigma_i$ such that for every finite set $F\subset …
22
votes
2
answers
2k
views
Can one view the Independent Product in Probability categorially?
One can construct a category of probability spaces, but this category has no products. Now probability theory relies strongly on the ability to build independent products, the product measure. In a se …
2
votes
1
answer
393
views
From universal measurability to measurability
Let $(\Omega,\Sigma)$ be a measurable space and $K$ be a compact
metrizable space endowed with its Borel $\sigma$-algebra
$\mathcal{B}(K)$. Let $A\subseteq\Omega\times K$ be universally
measu …
19
votes
2
answers
4k
views
Can we put a probability measure on every $\sigma$-algebra?
The following question has puzzled me for some time:
Let $(\Omega,\Sigma)$ be a nonempty,
measurable space. Does there
necessarily exist a probability
measure $\mu:\Sigma\to[0,1]$?
If the …
4
votes
0
answers
116
views
Is the range of a probability-valued random variable with the variation topology (almost) se...
Let $X$ and $Y$ be uncountable Polish spaces, $\Delta(Y)$ be the space of Borel probability measures on $Y$ endowed with the Borel $\sigma$-algebra induced by the variation distance, and let $g:X\to \ …