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9 votes
2 answers
361 views

Smooth rank one foliations with closed leaves

When the foliation is (transversally) Riemannian, this is proven in the book "Riemannian Foliations" by P. Molino. …
Misha Verbitsky's user avatar
5 votes

Smooth rank one foliations with closed leaves

Wadsley, Geodesic foliations by circles, J. Differential Geometry {\bf 10} (1975), no. 4, 541--549.) …
Misha Verbitsky's user avatar
4 votes
0 answers
152 views

Calabi–Yau theorem and complex Monge–Ampère equation for transversally Kähler manifolds

For taut foliations, one has also Poincaré duality on the basic cohomology, and the identification between the basic cohomology and the basic harmonic forms if a transversal Riemannian structure is given …
Misha Verbitsky's user avatar
3 votes

Foliations by holomorphic curves on complex surfaces

This is a question which is related to Lagrangian foliations on hyperkaehler manifolds, but much of the results are conjectures, or unpublished. … The tangent bundle of a general non-algebraic K3 has no rank 1 coherent subsheaves, hence this K3 has no holomorphic foliations. …
Misha Verbitsky's user avatar
2 votes

Is a linear vector field a geodesible vector field?

This observation seems to be very easy, but it takes care of many examples. Suppose that $A$ corresponds to a contraction (that is, all eigenvalues are $< 1$ in absolute value). Decompose ${\Bbb R}^n …
Misha Verbitsky's user avatar