Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options not deleted user 2900

For questions on modules over rings.

0 votes
0 answers
165 views

on the ``generic" modules of finite length (skyscrapers)

More precisely, consider the modules of finite length, with presentation matrix of size $m\times n$, i.e. the minimal resolution begins as: $\cdots\rightarrow R^n\rightarrow R^m$. … What is known about the "non-generic" modules? (Some stratification by the ``degeneracy type"?) …
Dmitry Kerner's user avatar
2 votes
0 answers
134 views

some sort of 'saturation' of module quotients

$R=k[[x_1,\dots,x_{p>1}]]$) Given two $R$-modules, $N\subset M$, of the same (finite, non-zero) rank. Their quotient, $M/N$, is torsion. I guess not much can be said in general. …
Dmitry Kerner's user avatar
2 votes
1 answer
191 views

what are the possible approximations for ideals

Of course, the same question holds for modules, but then it's more difficult …
Dmitry Kerner's user avatar
3 votes
0 answers
318 views

a generalization of the annihilator of cokernel ideal (some new invariants of modules?) [closed]

Let $R$ be a (commutative, associative, unital) ring, consider a homomorphism of some (finitely generated) free $R$-modules $E\stackrel{A}{\rightarrow}F$. Say $rank(F)=m$. … These seem to be some very natural (and simple) invariants of modules. Probably well known? References? ps. Shame on me, these are precisely the invariants described in Eisenbud's Comm.Alg. …
Dmitry Kerner's user avatar
1 vote
1 answer
602 views

When fitting ideals determine the module?

(at least, for regular local rings, for Gorenstein rings of low dimensions, for Cohen-Macaulay modules...) Any strengthening of such "fitting type" invariants that determines the module? upd. … Then $coker(A)$ and $coker(A^T)$ have the same fitting ideals, though the modules are non-isomorphic in general …
Dmitry Kerner's user avatar