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Homotopy theory, homological algebra, algebraic treatments of manifolds.
7
votes
In a fibration, can a deformation retraction of the base be lifted to the total space?
To clarify one point in the previous answers of Jeff and Mark: There are two different definitions of "deformation retraction" that are often used. In the stronger notion the subspace has to be poin …
28
votes
How to compute $\pi_{3}$ of $L(p,q)\# L(p',q')$?
One can compute $\pi_3$ completely by using the fact that it is isomorphic to $\pi_3$ of the universal cover. For a connected sum $M=P\# Q$ of lens spaces $P$ and $Q$ one obtains the universal cover $ …
14
votes
Accepted
Can H-space multiplication always be straightened so that mult.-by-id. is the identity on th...
There are three possible definitions of an H-space, according to whether the "identity" element is a strict left and right identity, or only an identity up to basepoint-preserving homotopy, or just up …
35
votes
Why do the homology groups capture holes in a space better than the homotopy groups?
Homology also has complicated and unintuitive aspects if one goes beyond nice spaces like CW complexes. A surprising example of this is the subspace of Euclidean 3-space consisting of the union of a c …
18
votes
Accepted
Poincaré Duality for non-compact manifolds without Zorn's Lemma
Often the definition of a manifold includes a condition to exclude strange manifolds that are "very large" such as the Prüfer surface. One condition commonly assumed is that the topology on the manifo …
6
votes
A homology of p-covering space
Here is an example of a $p$-sheeted covering space $X\to Y$ such that $H_1(X)$ has an element of order $p$ but $H_1(Y)$ is free. The space $X$ is the union of two pieces: a torus $A$ and surface $B$ o …
17
votes
Spaces with both "simple homology" and "simple homotopy" at the same time
There are many $K(G,1)$ spaces with nicely computable homology groups. Besides the ones you listed, there are many compact 3-manifolds of this type. Also various configuration spaces such as the space …
7
votes
Accepted
Moore decomposition, dual to Postnikov tower
This isn't really an answer but it's a bit long for a comment.
Do you really mean cohomology rather than homology? The dual of a Postnikov tower is usually considered to be a homology decomposition, …
26
votes
Accepted
Homology equivalence and isomorphism on $\pi_1$ not enough for homotopy equivalence?
Let $X$ be the CW complex obtained from $S^1 \vee S^n$, $n>1$, by attaching an $(n+1)$-cell via a map $S^n\to S^1\vee S^n$ representing the element $2t-1$ in $\pi_n(S^1\vee S^n) \cong {\mathbb Z}[t,t^ …
77
votes
Accepted
Definition of "simplicial complex"
Simplicial sets and simplicial complexes lie at two ends of a spectrum, with Delta complexes, which were invented by Eilenberg and Zilber under the name "semi-simplicial complexes", lying somewhere in …
14
votes
Deeper meanings of barycentric subdivision
In the other replies there has been some mention of alternative methods for subdivision besides barycentric subdivision, but these are rarely encountered in algebraic topology. What are some of these …
60
votes
Accepted
Intuition behind Thom class
It is easy to understand the existence of a Thom class by considering cellular cohomology. Let the given vector bundle be $E\to B$ with fibers of dimension $n$. One can assume without significant lo …
7
votes
Equivalence relations of topological spaces not comparable with homotopy
Here is a simple-minded example that is probably not the sort of thing you are looking for since it is not defined in terms of maps. For a topological space $X$ define its "local homology spectrum" to …
7
votes
Inverse cohomological isomorphisms
Some further comments on homology spheres: First, for any closed connected orientable $n$-manifold $M$ there is always a degree $1$ map $M\to S^n$ obtained by collapsing the complement of an open bal …
10
votes
One question on cup product and torsion elements
Here's an example that's a 2-dimensional CW complex. Start with a 0-cell, then attach three 1-cells labeled $a$, $b$, $c$ to get a wedge of three circles, then attach a 2-cell via the word $aba^{-1}b^ …