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8 votes
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Arithmetic points are dense on a Hida family

Hida theory is a vast domain of research. I am assuming that that you are in the simplest and oldest setting: Hida theory for ordinary eigencuspforms for the group $\operatorname{GL}_2$ over $\mathbb …
Olivier's user avatar
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7 votes
3 answers
2k views

Free subquotient of Galois representations coming from Hida theory

Let $\mathbf{T}$ be the reduced nearly ordinary Hecke algebra of level $N$ of Hida theory for $\operatorname{GL}_{2}$ over $\mathbb{Q}$ (or more generally over a totally real field $F$). Then $\mathbf …
Olivier's user avatar
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5 votes
Accepted

Existence of congruences between modular forms / elliptic curves

Given an eigencuspform $f$ of weight $k≥2$ (so in particular 2) and $p$ a prime of ordinary reduction (in particular good ordinary reduction), there is always a Hida family passing through $f$. This …
Olivier's user avatar
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3 votes

Example of a non-smooth irreducible component of the generic fibre of a Hida family?

This is an answer of rather low quality, but let me report that in several discussions about this topic with (many) experts over the span of many years, I have neither met anyone knowing of such an ex …
Olivier's user avatar
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3 votes

Periods for 2-variable p-adic L-functions

Assuming you are writing about Mok's Compositio 2009 article, the answer is easy: it's a question of quantifier ordering. There are two statements which you could call the interpolation property for a …
Olivier's user avatar
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2 votes

Interpolation of periods for a Hida family of modular forms

(1) The answer is yes. In fact this was done by Ohta himself essentially simultaneously as the other cases. The relevant publication is here (the proof in the case $k\equiv 2$ is around 569/570). (2) …
Olivier's user avatar
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1 vote

Atkin--Lehner operators in Hida theory

Like yourself, I have found a reference for these results hard to find, even in the case of Hida families. These are a few pointers. In the case of Hida families, once the Atkin-Lehner involutions ar …
Olivier's user avatar
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