Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options not deleted user 2191

The first purpose of schemes theory is the geometrical study of solutions of algebraic systems of equations, not only over the real/complex numbers, but also over integer numbers (and more generally over any commutative ring with 1). It was finalized by Alexandre Grothendieck, during the 1950s and the 1960s.

0 votes

Arbitrary products of schemes don't exist, do they?

If you want a tensor product satisfying the isomorphism described, you can just define it as the inductive limit of all finite tensor products. For example, if you tensor $k[x_i]$ like this you really …
Mikhail Bondarko's user avatar
0 votes
0 answers
150 views

An (almost) terminological question: could one shorten the phrase 'the spectrum of the resid...

For a scheme S I want to consider the spectra of the residue fields of points of S. Is there any way to make this phrase shorter? Is there a term for the morphism that connects such a spectrum with S? …
Mikhail Bondarko's user avatar
5 votes
1 answer
681 views

For a morphism f from a regular scheme, should there exist an open subscheme U of the target...

All schemes are excellent. If the answer is 'yes', then: could one choose such an $U$ such that the preimage of any regular subscheme of $U$ is regular? Are these conditions on $U$ equivalent? …
Mikhail Bondarko's user avatar
4 votes
1 answer
450 views

If $f:X\to S$ is a universal homeomorphism, is $f':X\times_S X\to X$ a nil-immersion?

If $f:X\to S$ is a universal homeomorphism, is $f':X\times_S X\to X$ always a nil-immersion? This seems to be easy, yet possibly I miss something. Should I give references to this fact in a paper?
Mikhail Bondarko's user avatar
5 votes
1 answer
1k views

Model of a scheme regular over the generic point

Let all schemes below be excellent. Let $X_0$ be a regular (not necessarily smooth, projective) non-empty scheme of finite type over the generic point $\eta$ of a regular connected scheme $S$. …
Mikhail Bondarko's user avatar
6 votes
0 answers
222 views

If $X,Y$ are regular and of finite type over $S$, can $X\times _S Y$ be embedded into a regu...

Now, I am interested in the following setting: $X,Y$ are regular schemes of finite type over $S$; $S$ is separated excellent noetherian of finite Krull dimension (and one may assume that $X$ and $Y$ are …
Mikhail Bondarko's user avatar
2 votes
0 answers
175 views

Regular subscheme of a projective limit of schemes

I am actually only interested in equicharacteristic schemes, and the connecting morphisms are affine and dominant. …
Mikhail Bondarko's user avatar
2 votes
1 answer
1k views

Is every regular (excellent) scheme separated?

I need schemes that are regular, excellent and separated. Are these three conditions independent? …
Mikhail Bondarko's user avatar
2 votes
0 answers
368 views

Can any radiciel morphism be presented as the composition of a universal homeomorphism with ...

As in my previous questions, I am interested in excellent schemes of finite Krull dimension. …
Mikhail Bondarko's user avatar
0 votes
0 answers
256 views

How would you call a subscheme of a smooth $S$-scheme?

In my preprint I propose to call $X/S$ quasi-smooth if $X$ can be embedded into a smooth $X'/S$. Does this sound fine? Upd. So, smoothly embeddable is better? Is it ok to call a morphism smoothly emb …
Mikhail Bondarko's user avatar
3 votes
0 answers
361 views

A presentation of a scheme as a limit of smooth ones over finitely generated bases

Which of the following statements are true: If $S$ is regular, then it can be presented as a projective limit of smooth $\mathbb{Z}$-schemes. … If $S$ is regular, then it can be presented as a projective limit of schemes that are smooth over finite type regular $\mathbb{Z}$-ones. …
Mikhail Bondarko's user avatar
4 votes
2 answers
331 views

Is the pre-image of a regular subscheme with respect to a universal homeomorphism of regular...

Let $f:X\to Y$ be a universal homeomorphism of regular (excellent finite-dimensional) schemes, $Z\subset Y$ be a regular subscheme. Is $f^{-1}(Z)$ necessarily regular? …
Mikhail Bondarko's user avatar
4 votes
1 answer
817 views

When singular points of a reduced scheme are not dense in it?

A stupid AG question: could singular (Zarisky) points be dense in a reduced (Noetherian) scheme $S$? If yes, which 'standard' restrictions on $S$ could ensure that this does not happen? For example, s …
Mikhail Bondarko's user avatar
6 votes
0 answers
305 views

Does one need l to be invertible in S in order to consider the l-adic cohomology of S-scheme...

What happens with $\mathbb{Q}_l$-adic cohomology of schemes if $l$ is not invertible in $S$ (but is not equal to the characteristic of $S$)? Will the Tate twist be invertible? …
Mikhail Bondarko's user avatar
6 votes
1 answer
814 views

More on universal homeomorphisms

Is a universal homeomorphism of connected regular (excellent finite dimensional) schemes an isomorphism if these schemes are not positive characterstic ones? … Suppose that a finite morphism $f:X\to Y$ of connected regular (excellent finite dimensional) schemes is generically purely inseparable. …
Mikhail Bondarko's user avatar

15 30 50 per page