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Numerical algorithms for problems in analysis and algebra, scientific computation

3 votes
Accepted

What is a one-parameter Newton's method?

"One-parameter family" simply means that one real parameter, $p$, appears in the definition. That method is simply a generalization of Newton's method exposed in the first equation; you can't derive i …
Federico Poloni's user avatar
2 votes

The bubble function

It is defined that way so that its maximum is exactly 1: $\|\phi_b(X)\|_{\infty}=1$.
Federico Poloni's user avatar
1 vote
Accepted

solving non linear equations

To answer completely, one should know what is the application that you have in mind and if there is any specific convergence result for the Newton method. But, in general, I think that you are right: …
Federico Poloni's user avatar
2 votes
Accepted

Stability of Levinson-Durbin method for Toeplitz system solutions ?

It can be unstable, and the condition number is not an adequate measure to tell when it fails. You may want to check the numerical experiments in http://www.jstor.org/stable/2153371 for specific examp …
Federico Poloni's user avatar
4 votes
Accepted

Newton-Raphson with multiple root

I suspect that using the expm1 function would give you a better result. Computing $e^x -1$ with the trivial formula in machine precision gives you only limited accuracy for small inputs: the fundament …
Federico Poloni's user avatar
2 votes

eigenvalues by matrix factorisation, e.g. QR

I suggest you to take a look at Watkins' book "The Matrix Eigenvalue Problem - GR and Krylov subspace methods". It is very well written and will give you insight on the working of the QR method. I thi …
Federico Poloni's user avatar
7 votes
Accepted

Condition number related to root finding problems

In addition to the convergence speed (and radius) mentioned in Pietro Majer's answer, there is another factor: if the problem is ill-conditioned, the solution is sensitive to perturbations. If you m …
Federico Poloni's user avatar
3 votes

Fast and reliable positive real root of cubic

One possibility is numerical rootfinding. A few iterations of Newton's method should get you home, and I imagine that for a third-degree polynomial one can construct (by sketching a plot of the functi …
Federico Poloni's user avatar
1 vote

solving series of linear systems with diagonal perturbations

If you're doing a full LU decomposition and ignoring sparsity, then you could switch to a Schur decomposition (costs $25n^3$ instead of $2/3n^3$, but allows you to solve any of the resulting systems w …
Federico Poloni's user avatar
0 votes

Numerical Solution to Inverse Integral (Pseudo Random Number Generation)

Newton's method? The derivative should be fairly straightforward to compute...
Federico Poloni's user avatar
0 votes

Making MATLAB svd robust to transpose operation

If you compute the (HO)SVD by solving the two eigenproblems, you always need to do some post-processing to sort the singular values and make them positive. I'd suggest moving the normalization issue …
Federico Poloni's user avatar
1 vote

Newton's Method for Finding Multiple Roots

Another good choice is the Aberth method http://en.wikipedia.org/wiki/Aberth_method. It has some advantages wrt the QR-based approaches, especially when the coefficients have very different magnitude …
Federico Poloni's user avatar
16 votes
Accepted

Are there ill-conditioned problems in infinite precision arithmetric?

Ill-conditioning isn't a concept that depends on the precision that you use to compute the solution. "A small change in the data turns into a large change of the solution" isn't a concept that involve …
Federico Poloni's user avatar
2 votes

Nested root finding algorithm

There's a third option I'd consider: alternated iterations. Namely, call $N[p]$ the Newton iteration for a function $p(x)$, and solve $$ z_{k+1}=N[h](z_k) $$ $$ y_{k+1}=N[g(\cdot,z_{k+1})](y_k) $$ ` …
Federico Poloni's user avatar
2 votes

Numerically differentiated values and their corresponding x-coordinates

A variant of the argument in Carlo Beenakker's answer: if the $x_i$ are equispaced points with distance $h$ one from the next, then $$\frac{f(x_{i+1})-f(x_i)}{h} - f'(x_i) = O(h),$$ $$ \frac{f(x_{i+1} …
Federico Poloni's user avatar

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