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first-order and higher-order logic, model theory, set theory, proof theory, computability theory, formal languages, definability, interplay of syntax and semantics, constructive logic, intuitionism, philosophical logic, modal logic, completeness, Gödel incompleteness, decidability, undecidability, theories of truth, truth revision, consistency.

17 votes
3 answers
3k views

Did Edward Nelson accept the incompleteness theorems?

Edward Nelson advocated weak versions of arithmetic (called predicative arithmetic) that couldn't prove the totality of exponentiation. Since his theory extends Robinson arithmetic, the incompleteness …
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9 votes
1 answer
473 views

What can $I\Delta_0$ prove?

What combinatorial and number-theoretic propositions can $I\Delta_0$ prove? Obviously there are an infinitude of them, but what are some well known theorems that can be proved in $I\Delta_0$, if any?
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7 votes
2 answers
603 views

Incompleteness theorems for theories with omega-rule

Recall that the omega-rule is an infinitary rule of inference that allows one to deduce $\forall x A(x)$ from $A(0), A(1), \dots$. It's known that adjoining PA (or even Q) with the omega-rule results …
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4 votes
0 answers
545 views

Can Robinson arithmetic prove any interesting theorems?

The motivation for my question is I'm curious whether studying Robinson arithmetic can be fruitful in the same sense as studying group theory. Robinson arithmetic is so weak that there are many struct …
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3 votes
0 answers
191 views

Set theories that are complete modulo finite-order arithmetic

In a previous question, I asked whether there can be effectively axiomatizable set theories (at least as strong as, say, ZF) that are complete modulo first-order arithmetic, to which the answer is no; …
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2 votes
1 answer
123 views

Special classes of the arithmetical hierarchy of sentences of finite-order arithmetic

We work in a countable language of finite-order arithmetic, which allows us to quantify over natural numbers, sets of natural numbers, sets of sets of natural numbers, and so on. We measure the comple …
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0 votes
0 answers
128 views

An arithmetic hierarchy without bounded quantifiers

I posted this question on math.stackexchange.com with no answers (https://math.stackexchange.com/questions/4337852/an-arithmetic-hierarchy-without-bounded-quantifiers). Let $\exists_n$ formulas in the …
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