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Stable homotopy theory is that part of homotopy theory (and thus algebraic topology) concerned with all structure and phenomena that remain after sufficiently many applications of the suspension functor.
19
votes
Accepted
Homotopy extension of $E_{\infty}$-spaces
This is probably belaboring the obvious, but just take seriously the equivalence between grouplike $E_{\infty}$ spaces and connective spectra. See for example
Equivalence between $E_\infty$-spaces …
20
votes
Accepted
Is the $\infty$-category of spectra “convenient”?
My colleague Dylan answered first (I keep telling him not to spend too much time on this toy :) but I both agree and disagree with his "Yes of course". The same words are used with different meanings …
4
votes
Accepted
Models for equivariant genuine commutative ring spectra
For the questions asked here, there is no difference between orthogonal $G$-spectra,
symmetric $G$-spectra of either $G$-spaces or $G$-sSets, or EKMM $G$-spectra. For
the first two, the nonequivaria …
23
votes
Why do homotopy theorists care whether or not $BP$ is $E_\infty$?
I suppose I should try to answer since the question of whether or not $BP$ is an $E_{\infty}$ ring spectrum
was Problem 1 of "Problems in infinite loop space theory'', http://www.math.uchicago.edu/~ma …
4
votes
Is there a map of spectra implementing the Thom isomorphism?
I just noticed this question, so my apologies for a very belated answer. Proposition 20.5.5 of http://www.math.uchicago.edu/~may/EXTHEORY/MaySig.pdf states that a $k$-orientation of a spherical fibra …
2
votes
Accepted
Where can I find basic "computations" of equivariant stable homotopy groups?
Since Denis gave the right reference, namely http://www.math.uchicago.edu/~may/BOOKS/equi.pdf, I did not follow up and answer this question. We can work with any compact Lie group and any complete un …
4
votes
$RO(G)$-graded homotopy groups vs. Mackey functors
A. The brackets are the same computed in any model, as you say, and for most that entails
fibrant approximation. For genuine $G$-spectra (complete universe), $G$ a compact
Lie group, it goes back …
17
votes
What is a simplicial commutative ring from the point of view of homotopy theory?
I have nothing non-trivial and non-digressive to say, but it might help to
point out in an elementary way some things that may be relevant. One way to think
about things is that there are distinction …
7
votes
What (if anything) unifies stable homotopy theory and Grothendieck's six functors formalism?
You can find an elementary categorical comparison of different contexts of the sort you ask about in a paper by Halvard Fausk, Po Hu, and myself, entitled ``Isomorphisms between left and right adjoint …
3
votes
When was the word "stable" first used to describe stable homotopy theory?
I like Lennart's comment so, Drew, I won't try to say much more. Stability in the first sense was certainly well understood by the very early 1950's, and it would be hard to be certain of a ``first'' …
6
votes
Accepted
Technology for various models of spectra
I don't think I noticed this question before. One point is that now that we
have multiplicatively well-behaved Quillen equivalences between all reasonable
models for the stable category, hence betwe …
11
votes
Accepted
Must a weak homotopy equivalence induce an isomorphism between stable homotopy groups?
Let's be precise about the question! I claim it is
not meaningful until you choose basepoints in X and
Y and restrict to based maps, since otherwise the
suspension used to define the stable homotopy …
3
votes
Classifying triangulated structures on a graded category
In 2002, Paul Balmer wrote a nice two page note answering the same question.
He sent it to me because I had asked the same question in my paper ``The
additivity of traces in triangulated categories'' …
6
votes
Mayer-Vietoris Sequence for Arbitrary Bicartesian Square of Spectra
I didn't want to answer this because the question seemed too
elementary to spend time on. But to see quasicategories invoked for something
so classically elementary is truly painful. (Forgive me Dyl …
8
votes
Accepted
Filtration on Smash Product of Cofibers
This is an excellent question that I have thought a lot about. I'd rather answer it in a more general context that was motivated by what I knew to be true in the stable homotopy category. The referen …