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11
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answers
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distribution of $\sqrt{-1} \mod p$
While reading up on quadratic reciprocity, I learned that if $p = 4k+1$ then $-1$ has a square root in $\mathbb{Z} / p \mathbb{Z}$.
Let $r_p$ be an integer with $0\leq r_p < p$ and $r_p^2 \equiv -1 \ …
8
votes
1
answer
453
views
higher reciprocity theorems from ratios of Gauss sums
One recent proof of quadratic reciprocity involves computing various rations of the Gauss sum.
In Quadratic reciprocity and the sign of the Gauss sum via the finite Weil representation Gurevich, …