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Partial differential equations (PDEs): Existence and uniqueness, regularity, boundary conditions, linear and non-linear operators, stability, soliton theory, integrable PDEs, conservation laws, qualitative dynamics.

3 votes

A non-linear PDE

I would set $u_x=v$ and reformulate the problem as $$v_t(x,t)=-(1-\int_1^x v(y,t)\,dy)^n, v(x,0)=0.$$ In this formulation, existence, uniqueness and numerical solution all become fairly straightforwar …
Michael Renardy's user avatar
1 vote

Integrable solutions to an elliptic PDE on divergence form have a definite sign

A formal argument is to integrate both sides over the region where u>0. The integral of the right hand side is zero, while the integral of the left hand side yields something strictly positive if ther …
Michael Renardy's user avatar
1 vote

Stokes problem; naive question on the regularity of pressure term

In fact, under reasonable assumptions on $\Omega$, you do get $u\in H^2$ and $p\in H^1$. However, this needs the regularity theory for elliptic systems, it does not follow from the calculus of variati …
Michael Renardy's user avatar
1 vote
Accepted

Well-posedness of Euler-Poisson system for semiconductors

Peter Markowich has worked extensively on this type of problem. Just look up his publications on Math Reviews.
Michael Renardy's user avatar
3 votes

Non-Normal derivative boundary conditions for a PDE

There is an extensive literature on oblique derivative boundary conditions. A Google search with the keyword "oblique derivative" will get you started.
Michael Renardy's user avatar
3 votes
Accepted

Uniqueness of weak solution L[u]=0

If $Lu=0$, then the Fourier transform of $u$ must have its support on the manifold where the symbol of $L$ is zero. Hence the Fourier transform of $u$ cannot be a function. This rules out $u\in L^p$ f …
Michael Renardy's user avatar
2 votes
Accepted

Test function .

No. Take any line through the support of $\eta$. Along such a line, you would have $|d\eta/ds|\le C|\eta|$. But since $\eta=0$ on a part of the line, you get $\eta=0$ everywhere by Gronwall's inequali …
Michael Renardy's user avatar
4 votes
Accepted

Lower bound on the solution of a Schrödinger-type equation

Here are a couple of ideas: 1 This yields a lower bound, but it is not in terms of a norm of f: Let $\lambda=\min(f/V)$. Then $u-\lambda$ satisifies $$-\Delta(u-\lambda)+V(u-\lambda)=f-\lambda V\ge …
Michael Renardy's user avatar
1 vote

The approximation to perturbed KdV Equation

There are techniques other than the inverse scattering method to solve the KdV equation: energy estimates, semigroup theory etc. These techniques can be used to prove differentiability with respect to …
Michael Renardy's user avatar
3 votes
Accepted

2d incompressible Euler equations under periodic boundary conditions

A famous result of Beale, Kato and Majda shows that the maximum norm of the vorticity has to become infinite if smooth solutions do not exist globally. This is true even in three dimensions. In two di …
Michael Renardy's user avatar
2 votes
Accepted

degree theory for elliptic equations; special solutions

The whole point of degree theory is its topological invariance. Now consider a saddle node bifurcation where you have a change from no solution to a stable and an unstable solution. This example shoul …
Michael Renardy's user avatar
3 votes

If $u \in L^2(0,T;X_0)$ with $u_t \in L^2(0,T;X_2)$, then is $u \in L^\infty(0,T;X_1)$?

This is true if $X_1=[X_2,X_0]_{1/2}$ (complex interpolation space), and this result is sharp. You will find this in many texts, e.g. Lions-Magenes.
Michael Renardy's user avatar
1 vote

Solvability of quasilinear elliptic equations on closed manifolds

No. Consider the case of periodic solutions in one dimension, and let c=1. That is, we have the equation $$u''+(u')^2=f.$$ Multiply both sides by $e^u$. You end up with $$(e^u)''=e^uf.$$ Now if, for i …
Michael Renardy's user avatar
2 votes

Mathematical difference between entropy and energy

Unfortunately, the PDE community has thoroughly confused this issue by using the word entropy for what physicists would call free energy. Therefore, if you are a physicist, entropy increases, but if y …
Michael Renardy's user avatar
0 votes

Question regarding to the basis of L^p space via compact self adjoint operators. ( eg: inver...

The operator which maps the function f(x) to $\int_0^x f(y)dy$ is compact, but it has no eigenfunctions. So the answer to your second question is no, even for Hilbert space. Also, if we are not talkin …
Michael Renardy's user avatar

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