Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options not deleted user 121

Questions about the branch of algebra that deals with groups.

2 votes

What are these subgroups called?

It is the set-wise stabilizer of $S$ under the left regular action.
S. Carnahan's user avatar
  • 45.7k
0 votes
Accepted

Reductive groups question

I'm a little hesitant to say anything in the face of all the comments above, but I think Ana is asking for an answer to the following question: If $G$ is a reductive algebraic $k$-group, and we choose …
0 votes

Name this pro-$p$ group

It appears to be a $p$-adic analog of the lamplighter group.
S. Carnahan's user avatar
  • 45.7k
10 votes

Counting the Groups of Order n Weighted by 1/|Aut(G)|

Computational evidence suggests $g(n)$ varies wildly with $n$. When $n$ is a power of a prime, or has lots of small factors, $g(n)$ can be very large (I would guess $g(2^k)$ is superexponential in $k …
S. Carnahan's user avatar
  • 45.7k
17 votes

Monstrous Moonshine

I think the claim goes back to the 1979 paper "Monstrous Moonshine" by Conway and Norton, where they discuss the "defining property of 24": If $n$ is a positive integer such that $xy \equiv 1$ mod $n$ …
S. Carnahan's user avatar
  • 45.7k
5 votes

Embedding of Finite 2-groups

Any subgroup of $H \times K$ will have a subgroup of index at most 4 that is a product of two cyclic groups. This comes from intersecting with a fixed choice of cyclic subgroups of index 2 in each fa …
S. Carnahan's user avatar
  • 45.7k
6 votes

When and how is a group of order n isomorphic to a regular subgroup of equal order?

A permutation group is called regular if it is transitive and all stabilizers are trivial. Left multiplication yields a regular embedding of any group into its group of permutations (so the answer to …
S. Carnahan's user avatar
  • 45.7k
6 votes
Accepted

How can we formalize the naturality of certain characteristic subgroups?

The commutator subgroup of a group is given by a functor on the category whose objects are groups and whose morphisms are all homomorphisms. We can say the similar statement for the torsion subgroup …
S. Carnahan's user avatar
  • 45.7k
4 votes

Rotational symmetry group of QxQ

I might as well add another two interpretations of this group from the theory of algebraic tori - this should make the isomorphism between $SO_2(\mathbb{Q})$ and $\mathbb{Q}[i]^\times/\mathbb{Q}^\time …
S. Carnahan's user avatar
  • 45.7k
6 votes

Uses of the holomorph, Hol($G$) = $G \rtimes $ Aut($G$)

The holomorph is used in the theory of Hopf Galois structures. If L/K is a Galois extension with Galois group G, then isomorphism classes of K-Hopf algebras H such that there is an L-Hopf algebra iso …
S. Carnahan's user avatar
  • 45.7k
17 votes

Is there a formula for the size of Symplectic group defined over a ring $Z/p^k Z$?

From Christopher Perez's answer, we have $|Sp_{2n}(\mathbb{Z}/p\mathbb{Z})| = p^{n^2} \prod_{i=1}^n (p^{2i}-1)$. Following Johannes Hahn, we wish to determine the size of the kernel of the homomorphi …
S. Carnahan's user avatar
  • 45.7k
2 votes

Automorphism group objects

I can't give you a complete answer (perhaps an expert will come along...), but a Google search reveals that there is an exercise on page 213 of Mac Lane and Moerdijk, Sheaves in geometry and logic: a …
S. Carnahan's user avatar
  • 45.7k
11 votes
Accepted

Covering of a group by seven proper subgroups: Counterexample

The only theorem of Tomkinson I could find about this was in Tomkinson, M.J.. "Groups as the union of proper subgroups." Mathematica Scandinavica 81.2 (1998): 191-198. In section 3, he proves th …
S. Carnahan's user avatar
  • 45.7k
2 votes

presentation for GL(n,K)

I suggest you give Mariano a check mark. MathOverflow does not function properly when you change a question substantially after it has been correctly answered. Regarding your revised question, we ca …
S. Carnahan's user avatar
  • 45.7k
2 votes

non-abelian groups of prescribed order

If $m$ is big, you get a large family of nonabelian unipotent algebraic groups over $\mathbb{F}\_p$, and these yield the nonabelian p-groups. The standard examples include the group of $k \times k$ u …
S. Carnahan's user avatar
  • 45.7k

1
2 3 4 5
15 30 50 per page