Search Results
| Search type | Search syntax |
|---|---|
| Tags | [tag] |
| Exact | "words here" |
| Author |
user:1234 user:me (yours) |
| Score |
score:3 (3+) score:0 (none) |
| Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
| Views | views:250 |
| Code | code:"if (foo != bar)" |
| Sections |
title:apples body:"apples oranges" |
| URL | url:"*.example.com" |
| Saves | in:saves |
| Status |
closed:yes duplicate:no migrated:no wiki:no |
| Types |
is:question is:answer |
| Exclude |
-[tag] -apples |
| For more details on advanced search visit our help page | |
Results tagged with convex-analysis
Search options not deleted
user 106046
4
votes
0
answers
202
views
Sharp constant for inequality with convex functions
This is a follow up to this question, where the optimal constant was left open.
Let $P \subset \mathbb{R}^n$ be bounded, convex, and open. Let
\begin{equation}
\mathcal{H} := \{f : P \rightarrow \m …
- 1,095
2
votes
Orthogonal projection of a point centrally-symmetric closed convex subset of $\mathbb R^n$ n...
Fix $j \in \{1, ..., n\}$. As I understand your symmetry condition, for any $y \in C$, we have $y^{j, 0} \in C$ which is defined via $y^{j, 0}_i := y_i$ for $i \neq j$ and $y^{j, 0}_j = 0$. Then by th …
- 1,095