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A Banach space is a complete normed vector space: A vector space equipped with a norm such that every Cauchy sequence converges.
7
votes
1
answer
1k
views
Banach spaces with a certain separability property
In Ledoux and Talagrand's "Probability in Banach Spaces", for technical reasons they frequently assume that a Banach space $B$ has the property that the unit ball of $B^*$ contains a countable subset …
8
votes
1
answer
432
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Self-dual finite-dimensional complex normed spaces
Suppose $X$ is a complex normed space of dimension 2 or 3 and $X$ is isometrically isomorphic to its dual. Is $X$ a Hilbert space?
Remarks: There are easy counterexamples in the real case, and in hi …
3
votes
Convergence of Gaussian measures
In general, a sequence of Banach space-valued random variables $Y_n$ converges weakly to $Y$
if $f(Y_n)\to f(Y)$ for every $f\in X^*$, and $Y_n$ is tight in the sense that for each $\varepsilon > 0$ t …
3
votes
Accepted
Diameter of a metric on orbits under affine bijections of $n-$dimensional convex compact sets
I assume you also want your compact sets to have non-empty interior, hence positive volume.
The literature mostly deals with the related Banach-Mazur metric $d_{BM}(A,B)$, in which it is assumed that …
8
votes
What is an isomorphism of Banach spaces?
A variation of 2. is to let morphisms be isometries into, so that isomorphisms are surjective isometries.
The other categories that I have alluded to elsewhere are those studied in nonlinear function …
9
votes
Derandomizing random matrices
There is active interest in such results in high-dimensional geometry, and expander graphs have even been used explicitly as a tool. Take a look for example at this paper and the references on the se …
5
votes
Accepted
Convergence of Gaussian measures
Somehow I didn't register how strong the assumptions Tom was making were, hence the fact that my other answer missed the point.
Unless I'm still missing something, this is very easy. Say $Z$ is a Gau …
18
votes
3
answers
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views
What are the right categories of finite-dimensional Banach spaces?
This is inspired partly by this question, especially Tom Leinster's answer.
Let me start with some background. I apologize that this will be rather long, since I'm hoping for input from people who …
5
votes
What is the tensor product of $L^p(\bf R)$ with $L^q(\bf R)$?
As pointed out in the comments, there are many Banach tensor products, but there is indeed at least one which works nicely for $L^p\otimes L^p$.
In general, the algebraic tensor product $X\otimes Y^* …
4
votes
Accepted
The typical size of a random element in a Banach space
The inequality can't be true without additional assumptions. To see this, let $X = \ell_2^n$ and let $x$ have a spherically symmetric distribution and let $R = \Vert x \Vert$. Then $R$ is an essenti …