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4 votes
Accepted

Distribution of running maximum of a local martingale

This example appears in Roger's & Williams book Diffusions, Markov Processes and Martingales as an example of a local martingale which is not a proper martingale. …
George Lowther's user avatar
6 votes
Accepted

Stochastic integrals as honest martingales -- comparison criterion

there exists positive constants $c < C$ such that $$ c\mathbb{E}\left[[M]_t^{1/2}\right]\le\mathbb{E}\left[\sup_{s\le t}\vert M_s\vert\right]\le C\mathbb{E}\left[[M]_t^{1/2}\right] $$ for all cadlag martingales
George Lowther's user avatar
4 votes
Accepted

Stochastic integrals as honest martingales — exponential damping

Yes, in this case it is true that $p$ is a proper martingale! Note that your integrand $\exp\left(-\int_0^tr_u du\right)$ is an adapted, continuous, and decreasing process bounded by 1. So, the follow …
George Lowther's user avatar
10 votes

The only continuous martingales with stationary increments are Brownian motions

There do in fact exist continuous martingales with stationary increments which are not Brownian motions. …
George Lowther's user avatar
7 votes
Accepted

Compactness of the set of densities of equivalent martingale measures

As $dM_t=M_{t-}\,d\tilde N_t$ and $d[M,S]\_t=M_{t-}\,d[\tilde N,S]\_t$, $M$ and $[M,S]$ are local martingales so, by integration by parts, $MS$ is a local martingale. … By localization (replacing $M$ by $M^\sigma$ for a suitable stopping time $\sigma$ with $\mathbb{P}(\sigma\ge\tau) > 0$), we can assume that $M$ and $MS$ are both proper martingales. …
George Lowther's user avatar