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Anand
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Can singular continuous functions be viewed as vanishing distributions?

Hello,

The question might be too naive. I am just not very confident about it. Let $f$ be a singular continuous function on $R$. We have $\int f \psi d x=0$ for any test function $\psi\in\mathcal{D}(R)$ (smooth functions with compact support). So the singular functions are vanishing distributions. Am I right?

Thank you very much for any hints!

Anand

p.s. this is related to my previous post.

Anand
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