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Genus of binary quadratic forms: $f(x,y), g(x,y)$ in same genus if and only if represent same values in $(\mathbb Z/m\mathbb Z)^\ast$ for all $m$

In David Cox's book: Primes of the form $x^2+ny^2$, second edition, there is a theorem(Theorem 3.21, page 52) characterize whether two binary quadratic forms in the same genus. The contents of the theorem are:

Let $f(x,y)$ and $g(x,y)$ be primitive forms of discriminant $D\neq0$, positive definite if $D<0$. Then the following are equivalent:

(i) $f(x,y)$ and $g(x,y)$ are in the same genus, i.e., they represent the same values in $(\mathbb Z/D\mathbb Z)^\ast$.

(ii) $f(x,y)$ and $g(x,y)$ represent the same values in $(\mathbb Z/m\mathbb Z)^\ast$ for all nonzero integer $m$.

(iii) $f(x,y)$ and $g(x,y)$ are equivalent modulo $m$ for all nonzero integer $m$.

(iv) $f(x,y)$ and $g(x,y)$ are equivalent over the $p$-adic integer $\mathbb{Z}_p$ for all primes $p$.

(v) $f(x,y)$ and $g(x,y)$ are equivalent over $\mathbb Q$ via a matrix in $GL_2(\mathbb Q)$ whose entries have denominators prime to $2D$.

(vi) $f(x,y)$ and $g(x,y)$ are equivalent over $\mathbb Q$ without essential denominators, i.e., given any nonzero $m$, a matrix in $GL_2(\mathbb Q)$ can be found which takes one form to the other and whose entries have denominators prime to $m$.

The author does not give details of the proof, only some references.

Question: How to derive (ii) and (iii) from (i), and how to prove the equivalence of (iv) and (vi). Could someone please give me some hints?

HGF
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