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Tomasz Kania
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Does seperability of the strong operator topology imply separability of the underlying space?

Let $X$ be a Banach space and $B(X)$ be the space of bounded operators on $X$.

Suppose that the strong operator topology on $B(X)$ is separable and that the cardinal number of $B(X)$ is continuum.

Question. Can we conclude the norm topology on $X$ is separable?

Remark. It was proved by Tomek Kania that the assumption $|B(X)|=\mathfrak{c}$ is not solely enough to get the separability assertion.

ABB
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