Gibbs' inequality is equivalent to:
\begin{equation} \sum_{i} \ln q_i^{p_i}-\ln p_i^{p_i} \geq 0 \end{equation}
where $p_i,q_i \in [0,1]$ and $\sum_i p_i = \sum_i q_i=1$.
Now, a friend of mine suggested that:
\begin{equation} \sum_{i} \ln q_i^{p_i}-\ln p_i^{p_i} \geq 0 \implies \sum_{i} q_i^{p_i}-p_i^{p_i} \geq 0 \end{equation}
Right now I doubt this is true but I can't think of a counter-example.