I have a question of an explicit example of a busby invariant of a extension, which can be found in Blackadars book "K-theory for Operator Algebras".

Let $0\to B\to E\to A\to 0$ be a short exact sequence of $C^*$-algebras, in particular $A=\mathbb{C}$, $B=C_0((0,1))$. Now there are four possible choices of $E$, namely $C_0((0,1))\oplus \mathbb{C}, C_0((0,1]), C_0([0,1)), C(S^1)$.

Why only these 4 $C^*$-algebras, what is with $C^*$-algebras which are isomorphic to one of the possibilities enumerated above?

A busby invariant of this extension is a $\ast$-homomorphism $\tau:E/B\cong A\to M(B)/B$, where $M(B)$ is the multiplier algebra of $B$ and this homomorphism comes from the map $E\to M(B)$ (which arises from the universal property of multiplier algebras) composed with the quotient map $M(B)\to M(B)/B$.

For the extension above it is $M(B)\cong C(\beta\mathbb{R})$, where $\beta\mathbb{R}$ is the Stone-Čech compactification of $\mathbb{R}$ (with euclidean topology) and $M(B)/B\cong C(\beta \mathbb{R}\setminus \mathbb{R})$. I.e. $\tau$ must be a $*$-homomorphism $\tau:\mathbb{C}\to C(\beta \mathbb{R}\setminus \mathbb{R}) $ and for every choice of $E$ we get a specific $\tau$.

But (if we are in the situation that we do not know how many possible choices of $E$ we have), why are there only 4 possibilities of $*$-homomorphism $\tau:\mathbb{C}\to C(\beta \mathbb{R}\setminus \mathbb{R}) $ ? We have to determine the images of $1\in \mathbb{C}$ in every case, for example one possible choice of $\tau$ is if we set $\tau (1)=0$, but in the book the author enumerates the other possibilities $1$ sending to the characteristic function of the component at $-\infty$, the characteristic function of the component at $\infty$ and to $1$. I don't see why this should be all possibilities.

In addition to that, which of the choices of $\tau$ corresponds to $C(S^1)$ for example?

Regards