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Luka
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$p^3 | \sum_{i=1}^{p-1}\binom{p}{i}^2$ => $p | \sum_{i=1}^{p-1}\binom{p}{i}$?

For $p\in \mathbf{N}$ is $$p^3 \text{ divides } \sum_{i=1}^{p-1}\binom{p}{i}^2$$ impling $$p \text{ divides } \sum_{i=1}^{p-1}\binom{p}{i}$$?

Notice that the second condition is equvalent to say: "$p$ is a prime or $p$ is a Poulet number". Or

is $$p^4 \text{ divides } \sum_{i=1}^{p-1}\binom{p}{i}^2$$ impling $$p \text{ divides } \sum_{i=1}^{p-1}\binom{p}{i}$$? Notice that the first condition here is equvalent to say: "$p$ is a Wolstenholme number"

Luka
  • 121
  • 6