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On $XX'=I$ such that $AX=XB$ is true when $A,B\in\{0,1\}^{n\times n}$
Given real symmetric matrices $A,B\in\{0,1\}^{n\times n}$ is it true that $$AX=XB$$ has a solution of form $X$ a permutation matrix iff a solution with $XX'=I$ exists? We are over reals.
It is clear ...
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