Skip to main content

All Questions

Filter by
Sorted by
Tagged with
2 votes
1 answer
159 views

Field extensions and completions at possibly infinite places

In Serre's Corps Locaux, Chapter 2 §3, is presented a classical proof. We are in an "ABKL" setup, where $K/L$ is finite, $A$ is Dedekind, $B$ is the integral closure of $A$ and $B$ is $A$-...
Adrien Zabat's user avatar
6 votes
2 answers
329 views

Algebraic numbers which prescribed degree which does not belong to some fields

In my research it would be great if the following result is valid. In what follows, $\overline{\mathbb{Q}}$, $\overline{\mathbb{Q}}_n$ and $\overline{\mathbb{Q}}_{<n}$ denotes the set of algebraic ...
Jean's user avatar
  • 515
2 votes
0 answers
311 views

Degree $8$ cyclic extension over $\mathbb{Q}$

Actually I am interested in degree $ 8 $ cyclic extension over $ \mathbb{Q} $. Let $ L $ be such extension. At first I was thinking to take basis as normal basis, as we can determine the galois group ...
Sky's user avatar
  • 923
1 vote
0 answers
36 views

Quadratic suborders of an imprimitive quartic order

Let $Q$ be an irreducible quartic order; that is, $Q$ is a subring of the ring of integers $\mathcal{O}_K$ in a quartic extension $K$ over $\mathbb{Q}$ such that the fraction field of $Q$ is equal to $...
Stanley Yao Xiao's user avatar
8 votes
1 answer
4k views

Example of an algebraic number of degree 4 that is not constructible

The number $b:=\frac{\sqrt{2a}+\sqrt{4\sqrt{a^2-3}-2a}}{2}$ with $a:=\frac{\sqrt[3]{18+2\cdot\sqrt{65}}}{2}+\frac{2}{\sqrt[3]{18+2\cdot\sqrt{65}}}$ is a root of the irreducible polynomial $x^4-6x+...
Joel Adler's user avatar
6 votes
1 answer
951 views

Is it possible to recover the degree of a field extension from a list of elements and the ground field?

I'm interested to know if there is anything known about recovering the degree of a field extension, $E/k$, given $E=k(\alpha_1,\ldots, \alpha_n)$ (here I'm assuming that the extension is of finite ...
Adam Hughes's user avatar
  • 1,049