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6 votes
1 answer
168 views

Weak convergence of random measures generated by non-negative martingales?

If I have a sequence of non-negative continuous martingales $(M_n(x))_{n\ge 1}$ on $x\in[0,1]$, i.e. for each fixed $n$, $M_n:[0,1]\to[0,\infty)$ is a continuous process, and for each fixed $x\in[0,1]$...
MikeG's user avatar
  • 715
5 votes
1 answer
652 views

Proof of Pinelis (1992) - Banach space inequalities

I am reading Pinelis "An approach to inequalities for the distributions of infinite -dimensional martingales" and cannot follow his proof of Theorem 3: Let $(f_n)$ be a martingale in a separable ...
Manuel Schmidt's user avatar
4 votes
1 answer
443 views

Uniform martingale convergence of Radon-Nikodym derivatives of a convex set of probabilities

Cross posted at MSE here. I'm hoping someone here can help complete zhoraster's answer. Any hints or references are appreciated. Let $(\Omega, \mathcal{F})$ be a measurable space equipped with a ...
aduh's user avatar
  • 869
4 votes
1 answer
302 views

Zero-one law for an independence-like structure

I am a number theorist by profession, so apologies if the answer to this question is "trivially true" or "trivially false". Let $(\Omega, \mathcal{A}, P)$ be a (non-atomic) probability space. Let $(\...
Kurisuto Asutora's user avatar
1 vote
1 answer
83 views

Integral of $M^\text{*} - M$ with respect to $M^\text{*}$ is zero for $M^\text{*}$ the running maximum of $M$ a continuous local martingale

Given $M$ a continuous local martingale, and $M^\text{*} = \sup_{0 \leq s \leq t} M_s$ its running maximum, we consider the finite variation integral $$ I_T:= \int_0^T (M^\text{*}_s - M_s) \, \text{d}...
George's user avatar
  • 113
1 vote
1 answer
185 views

Sum of $X_k$ with $\mathbb{P}(X_k=\pm 1) = 1/2\pm 1/(2\sqrt{k})$

Let $\{X_k\}$ be a sequence of mutually independent random variables with \begin{align} \mathbb{P}(X_k = 1) & = \frac{1}{2} + \frac{1}{2\sqrt{k}}, \\ \mathbb{P}(X_k = -1) & = \frac{1}{2} - \...
Nuno's user avatar
  • 269
1 vote
1 answer
140 views

Does a sequence that verifies the assumptions of a square integrable martingale on some event need to be convergent on this event?

I came across this claim by reading some literature on stochastic approximation. Let $(\Omega, \mathcal{A}, \mathbb{P}$) be a probability space, $(\mathcal{F}_n)$ a filtration on it. Let $(\epsilon_{n}...
J. Doe's user avatar
  • 115
0 votes
0 answers
71 views

Conditions for existence of a semi-martingale representing a system of probability measures

Let $(\nu_t)_{t \in [0,1]}$ be Borel probability measures on a stochastic basis $(\Omega,\mathcal{F},(\mathcal{F}_{t \in [0,1]})_t,\mathbb{P})$. Does there exist a semi-martingale $(X_t)_{t\in[0,1]}$ ...
ABIM's user avatar
  • 5,405