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5 votes
1 answer
453 views

Every manifold can be cut into cubes

I saw the following statement in my advanced calculus text, which was presented without proof: If $\bar{D}$ is a compact domain in the plane (that is, closure of an open, connected and bounded subset ...
WhyNót's user avatar
  • 151
13 votes
1 answer
899 views

Critical dimensions D for "smooth manifolds iff triangulable manifolds"

I am aware that at least for lower dimensions, "smooth manifolds iff triangulable manifolds" at least for dimensions below a certain critical dimensions D. My question is that for For ...
wonderich's user avatar
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3 votes
0 answers
221 views

Category of Manifolds and Maps: TOP $\supseteq$ TRI $\supseteq$ PL $\supseteq$ DIFF? [closed]

Please let me denote the following (TOP) topological manifolds https://en.wikipedia.org/wiki/Topological_manifold (PDIFF), for piecewise differentiable https://en.wikipedia.org/wiki/PDIFF (PL) ...
annie marie cœur's user avatar
4 votes
0 answers
161 views

(Non-)Orientability of non-triangulable manifolds

We heard and learned from Mike Miller's answer to Not all manifolds can be triangulated: In which dimensions? that "All orientable 5-dimensional manifolds are triangulable. In dimensions at least ...
annie marie cœur's user avatar