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2 votes
1 answer
140 views

Does substitution on named terms correspond to substitution on de Bruijn terms?

Altenkirch wrote (in the unpublished draft α-conversion is easy): I leave it to the reader to show that (some natural translation function) preserves substitution, i.e. it maps substitutions on named ...
3 votes
1 answer
140 views

Where can I learn about Cartesian closed functors between categories of simply typed lambda calculus?

I'll try to describe the subject I am looking for literature on, or concept names that I can Google. For each $n \geq 1$, let $\mathbf{STLC}_n$ be the category where the objects are all simply typed ...
1 vote
0 answers
66 views

Posets with two partial (self-)distributive operations

Let $(X, {\sqsubset}, {\circ}, {\ast})$ be a set $X$ with a strict partial order $\sqsubset$ and two partial binary operations $\circ$ and $\ast$ such that for any $a, b, c \in X$: $a \circ b$ and $a ...
20 votes
5 answers
3k views

[solved] sequent calculus as programming language

intuitionistic logic ~ programming natural deduction ~ lambda-calculus Hilbert system ~ combinatory logic {S, K} Gentzen system=sequent calculus ~ ? What would you write in place of the question ...
2 votes
1 answer
327 views

Substructural types, the lambda calculus, and CCCs

It's well known that the simply-typed lambda calculus corresponds to a cartesian closed category. How would substructural type systems be characterized in category theory? For example, linear type ...
9 votes
2 answers
2k views

Is simply typed lambda calculus with fixed-point combinator Turing-complete?

There are many sources cite that simply typed lambda calculus extended with fixed-point combinator is Turing complete. For example, Does there exist a Turing complete typed lambda calculus? or the ...
10 votes
2 answers
2k views

Scott on the consistency of the lambda calculus

I have twice heard it attributed to Dana Scott that he said something to the effect that the consistency of the lambda-calculus was an accident. Does anyone have a reasonable-sounding source for this?...
2 votes
2 answers
181 views

Background for Kierstead terms

I was looking at some slides of John Longley's here, where he mentions "the Kierstead functional" $$\lambda f.f(\lambda x.f(\lambda y.x)) \ ,$$ (where $f$ should be of type $2$, and $x,y$ of ground ...