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2 votes
2 answers
64 views

Does $(\omega, E)$ with the cycle condition have an $\omega$-path?

Let $G = (V,E)$ be a simple, undirected graph. We say that $v\neq w\in V$ lie on a common cycle if there is an integer $n\geq 3$ and an injective graph homomorphism $f: C_n\to V$ such that $v,w\in \...
Dominic van der Zypen's user avatar
1 vote
2 answers
143 views

Does $\{0,1\}^{<\omega}$ have a Hamiltonian path?

Let $\{0,1\}^{<\omega}$ be the collection of $x \in \{0,1\}^\omega$ such that there is $N\in\omega$ with $x(k) = 0$ for all $k\geq N$. We say that $ x, y\in \{0,1\}^{<\omega}$ form an edge if ...
Dominic van der Zypen's user avatar
2 votes
1 answer
106 views

Hamiltonian path in divisibility graph

Let $\mathbb{N}$ denote the set of positive integers, and consider the graph $(\mathbb{N}, E)$ where a set $\{a,b\}$ of two distinct positive integers belongs to $E$ if there is an integer $k>1$ ...
Dominic van der Zypen's user avatar
2 votes
1 answer
118 views

$\omega$-Hamilton paths in $\mathbb{Z}^n$

For any set $X$ set $[X]^2 = \{\{x,y\}: x,y\in X, x\neq y\}$. If $n\geq 2$ is an integer, we endow $\mathbb{Z}$ with a graph structure in the following way. If $x,y\in \mathbb{Z}^n$ we say $x,y$ are ...
Dominic van der Zypen's user avatar
1 vote
0 answers
186 views

Countable graph that is "as non-traceable as it gets"

If $\omega$ denotes the set of the natural numbers (= the first infinite ordinal), and if $E\subseteq\binom{\omega}{2}$ is any subset, we call a map $f\colon\omega\to\omega$ a walk in the graph $(\...
Dominic van der Zypen's user avatar